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Alona [7]
3 years ago
11

1.) What are the two broad categories that elements can be divided into?

Chemistry
1 answer:
hoa [83]3 years ago
5 0

Answer:

1) Metals and nonmentals

2) Elements: Oxygen (O_{2} \\) , Nitrogen (N_{2}

3) Compounds: Carbon Dioxide CO_{2}, Methane CH_{4}, Nitrogen DioxideNO_{2}

Explanation:

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Scientific knowledge results from the interaction of scientists who are investigating natural phenomena. Which of these BEST des
seraphim [82]

Answer:

5ywhxhghghghfhffgffgffg

Explanation:

6 0
3 years ago
Find the equation of directrix of the parabola is given by 64x equals to -ySquare ​
ANEK [815]

Answer:

Given equation of parabola is

and

2

=64x ......(i)

The point at which the tangent to the curve is parallel to the line is the nearest point on the curve.

On differentiating both sides of equation (i), we get

2 y

dx

d y

=64

⇒

dx

d y

=

and

32

Also, slope of the given line is −

3

4

∴−

3

4

=

and

32

⇒and=−24

From equation (i), (−24)

2

=64x⇒x=9

∴ the required point is (9,−24)

Explanation:

This is the correct answer you want

please follow the

5 0
3 years ago
1.) What are the two broad categories that elements can be divided into?
hoa [83]

Answer:

1) Metals and nonmentals

2) Elements: Oxygen (O_{2} \\) , Nitrogen (N_{2}

3) Compounds: Carbon Dioxide CO_{2}, Methane CH_{4}, Nitrogen DioxideNO_{2}

Explanation:

5 0
3 years ago
21. _____ Which of the following entities has the greatest mass?
IrinaK [193]
I believe it’s D because phosphorus has the mass of 30.9.
8 0
3 years ago
a 4.18 g sample of a hydrocarbon is combusted in a bomb calorimeter that contains 974 g of water. the temperature of the water i
lys-0071 [83]

The heat of the reaction, in kJ, when 4.18 g of the hydrocarbon are combusted 775.70 kJ.

The heat energy is given as :

q = m c ΔT + Ccal ΔT

q = ( 974 g× 4.184 ×6.9) + 624 ×6.9

q = 32424.59 J

moles of hydrocarbon = 0.0418 mol

heat of combustion = 32424.59 J / 0.0418 mol

                                 = 775707.89 J

                                = 775.70 kJ

Thus, A 4.18 g sample of a hydrocarbon is combusted in a bomb calorimeter that contains 974 g of water. the temperature of the water increases by 6.9 °C when the hydrocarbon is combusted. the calorimeter constant for the calorimeter was determined to be 624 J/°C. what is the heat of the reaction is 775.70 kJ.

To learn more about calorimeter here

brainly.com/question/28943378

#SPJ4

5 0
1 year ago
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