The molar concentration of the original HF solution : 0.342 M
Further explanation
Given
31.2 ml of 0.200 M NaOH
18.2 ml of HF
Required
The molar concentration of HF
Solution
Titration formula
M₁V₁n₁=M₂V₂n₂
n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)
Titrant = NaOH(1)
Titrate = HF(2)
Input the value :
Following steps are involved in this reaction,
Nitration: Nitration of benzene yield nitrobenzene.
Reduction: Reduction of Nitrobenzene yield Aniline.
Diazotization: Diazonium alt of benzene is formed from aniline.
At last diazonium salt is reacted with CuCl to yield chlorobenzene.
Answer:
18
Explanation:
You add the two numbers on the bottom left (8 and 32) and then subtract the number On the bottom middle right (22) from it (40-22=18) and then the answer to that gives you the answer of how much water is produced.
hope that helped :)
1 - In what organelle or membrane are triacylglycerols synthesized and fatty acids elongated?
A - Lysosomes
B - Peroxisome
C - Endoplasmic reticulum
D - Ribosomes
E - Nucleus
The answer is Endoplasmic reticulum
PbCl₂(s) ⇄ Pb²⁺(aq) + 2Cl⁻(aq)
Pb(CH₃COO)₂(s) → Pb²⁺(aq) + 2CH₃COO⁻(aq)
At lead acetate disolution, concentration of lead cations will increase. According to Le Chatelie's principle equilibrium will be displaced towards formation of solid lead chloride.
