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AleksAgata [21]
3 years ago
6

CO2 + H20. What is the total number of moles of Oz required to completely

Chemistry
1 answer:
maria [59]3 years ago
7 0
I think the right answer is 2.5
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At a certain temperature, the vapor pressure of pure benzene ‍ is atm. A solution was prepared by dissolving g of a nondissociat
erastova [34]

Answer:

Molar mass of solute: 300g/mol

Explanation:

<em>Vapor pressure of pure benzene: 0.930 atm</em>

<em>Assuming you dissolve 10.0 g of the non-volatile solute in 78.11g of benzene and vapour pressure of solution was found to be 0.900atm</em>

<em />

It is possible to answer this question based on Raoult's law that states vapor pressure of an ideal solution is equal to mole fraction of the solvent multiplied to pressure of pure solvent:

P_{sln} = X_{solvent}P_{solvent}^0

Moles in 78.11g of benzene are:

78.11g benzene × (1mol / 78.11g) = <em>1 mol benzene</em>

Now, mole fraction replacing in Raoult's law is:

0.900atm / 0.930atm = <em>0.9677 = moles solvent / total moles</em>.

As mole of solvent is 1:

0.9677× total moles = 1 mole benzene.

Total moles:

1.033 total moles. Moles of solute are:

1.033 moles - 1.000 moles = <em>0.0333 moles</em>.

As molar mass is the mass of a substance in 1 mole. Molar mass of the solute is:

10.0g / 0.033moles = <em>300g/mol</em>

8 0
3 years ago
Check all statements below that are true.
docker41 [41]

Answer:

The answers are A,B,C.

Explanation: Just got it right on Edge 2020

3 0
3 years ago
A bike tire at a pressure of 2.4 atm and a
hjlf

Answer:

5.4 atm

Explanation:

P•V/T = P'•V'/T'

2.4•2.2/290 = P'•2/296

5.28/290 = P'/296 Multiply both sides by 296

1562.88/290 = P'

I'm = 5.4 atm

3 0
2 years ago
1. A light bulb is filled with 3.54 g of argon at 25 C and 725 mmHg. What is
Ugo [173]

Answer: The volume of given gas is 2.27 L.

Explanation:

Given: Mass = 3.54 g

Temperature = 25^{o}C = (25 + 273) K = 298 K

Pressure = 725 mm Hg (1 mm Hg = 0.00131579) = 0.95 atm

As moles is the mass of substance divided by its molar mass.

So, moles of argon (molar mass = 40 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{3.54 g}{40 g/mol}\\= 0.0885 mol

Formula used to calculate the volume of given gas is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times V = 0.0885 mol \times 0.0821 L atm/mol K \times 298 K\\V = 2.27 L

Thus, we can conclude that the volume of given gas is 2.27 L.

3 0
3 years ago
I need someone to answer this ASAP please!
yan [13]

Answer:

239.15. OR round down 239

Explanation:

3 0
3 years ago
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