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Sedbober [7]
3 years ago
5

On the basis of dipole moments and/or hydrogen bonding, explain in a qualitative way the differences in the boiling points of ac

etone (56.2 °c) and 1-propanol (97.4 °c), which have similar molar masses.
Chemistry
1 answer:
Inga [223]3 years ago
7 0
Go on google bro you can get more help there and hope you get what your looking for and good luck

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Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s−1 .
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Vanadium has an atomic mass of 50.9415 amu. It has two common isotopes. One isotope has a mass of 50.9440 amu and a relative abu
grandymaker [24]

Answer:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

Explanation:

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\huge{ \mathfrak{  \underline{ Answer \:  \:  ✓ }}}

The 2 in front of Na in 2Na + Cl_2 \rightarrow  2NaCl is <u>Coefficient.</u>

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Why was Becquerel’s experiment a first step in discovering radioactivity?
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