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Sedbober [7]
3 years ago
5

On the basis of dipole moments and/or hydrogen bonding, explain in a qualitative way the differences in the boiling points of ac

etone (56.2 °c) and 1-propanol (97.4 °c), which have similar molar masses.
Chemistry
1 answer:
Inga [223]3 years ago
7 0
Go on google bro you can get more help there and hope you get what your looking for and good luck

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How many electrons does Br lose or gain to fill its octet?
Greeley [361]

i think it is 8. I might be wrong.

4 0
3 years ago
An unknown element is shiny and is found to be a good conductor of electricity, what other properties would you predict for it
VLD [36.1K]
That it is hard, and a metal? 
3 0
3 years ago
rite stepwise equations for protonation or deprotonation of this polyprotic species in water. What are the products of the first
adoni [48]

<u>Answer:</u> The products of the given chemical equation are HCO_3^-\text{ and }OH^-

<u>Explanation:</u>

Protonation equation is defined as the equation in which protons get added in the substance.

The chemical equation for the protonation of carbonate ion in the presence of water follows:

CO_3^{2-}+H_2O\rightarrow HCO_3^-+OH^-

By Stoichiometry of the reaction:

1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion

Hence, the products of the given chemical equation are HCO_3^-\text{ and }OH^-

3 0
3 years ago
After undergoing alpha decay, an atom of radium-226 becomes
Zanzabum
The answer is b. radon-222. The alpha decay means that it will emit an alpha particle when decays. The alpha particle has two protons and two neutrons. So Radium(88) minus two protons will become Radon(86). And the atomic mass will become 226-4=222.
8 0
3 years ago
Please help me with this chem question, I’ll mark you brainiest if it’s right. There’s multiple answers for this one.
Kazeer [188]

Answer:

Option A. KCl (aq)

Option D. Mg(OH)₂(s

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

MgCl₂(aq) + KOH(aq) —>

In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

KOH(aq) —> K⁺(aq) + OH¯(aq)

MgCl₂(aq) + KOH(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)

MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)

Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)

Thus, option A and D gives the correct answer to the question.

8 0
3 years ago
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