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Sedbober [7]
3 years ago
5

On the basis of dipole moments and/or hydrogen bonding, explain in a qualitative way the differences in the boiling points of ac

etone (56.2 °c) and 1-propanol (97.4 °c), which have similar molar masses.
Chemistry
1 answer:
Inga [223]3 years ago
7 0
Go on google bro you can get more help there and hope you get what your looking for and good luck

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Which of the following is NOT a heterogenous mixture:
ANTONII [103]

Answer:Vinegar

Explanation:

4 0
3 years ago
When a hydrochloric acid solution is combined with
adoni [48]

Answer:

HCl(aq) + KOH(aq --> KCl(aq) + H₂O(l)

Explanation:

4 0
3 years ago
Are ions of alkali metals larger or smaller than ions of alkaline earth metals from the same period
PtichkaEL [24]
Because size of an atom INCREASES from top to bottom and DECREASES from left to right on the periodic table. If to elements are in the same period they can't increase in size based on the up or down trend. Instead, notice that Alkali Metals are LEFT of Alkaline Earth Metals. Therefore, the Alkali Metal will be larger than the Alkaline Earth Metals.
7 0
4 years ago
Cuando aumenta la temperatura dentro de un recipiente cerrado que contiene un gas este se expande/comprime por que las partícula
Evgesh-ka [11]

Answer:

expande

forman se alejan

Explanation:

Según las leyes de los gases ideales;

La ley de Charles establece que el volumen de una masa dada de gas ideal es directamente proporcional a su temperatura a la presión simultánea.

Esto significa que cuando se calienta una masa dada de gas ideal, el gas se expande y las moléculas de gas se alejan unas de otras de acuerdo con la ley de Charles.

7 0
3 years ago
If 37.5 mL of 0.100 M calcium chloride reacts completely with aqueous silver nitrate, what is the mass of AgCl (MM
Travka [436]

Answer:

OPTION C is correct

C) 1.07 g

Explanation:

CaCl2(aq) + 2 AgNO3(aq) → 2 AgCl(s) + Ca(NO3)3(aq)

But we know molarity molarity= number of moles of solute/ volume of the solution

M= n/V

From the equation above

number of moles of Cacl2 = (37.5 ×0 .100 × 10^-3) = 0.00375 moles.

Then

1 mole of Cacl2 yields 2 moles of Agcl2

0.00375 moles of Cacl2 will produce let say Y.

Y= (0.00375 ×2)/1

= 0.0075 moles.

Number of moles of Agcl2 = mass /molar mass of Agcl

Molar mass of Agcl = 178

Then mass = 178 ×0.0075 = 1.047

Therefore, the mass of agcl precipitate is

1.07 g

8 0
3 years ago
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