Question

If I have a 32 fl oz os a solution that has 62% alcohol, how much of a solution of 91% alcohol do I need to add to get a final solution of 90% alcohol?

Answer 1

Answer : The amount of solution needed is, 97.3 fl oz

Explanation :

Let the amount of solution needed be, x

Thus, the equation will be:

$(x\times 0.62)+(32-x)\times 0.91=0.90$

By solving the expression, we get the value of 'x'.

$0.62x+0.91\times 32-0.91x=0.90$

$0.62x+29.12-0.91x=0.90$

$-0.29x+29.12=0.90$

$-0.29x=0.90-29.12$

$-0.29x=-28.22$

$0.29x=28.22$

$x=\frac{28.22}{0.29}$

$x=97.3$

Therefore, the amount of solution needed is, 97.3 fl oz