Answer:
T = 530 N
, t = 12.65 s
Explanation:
This is an exercise on Newton's second law,
T - W = m a
where T is the tension of the cable, W the weight and the steel of the box
T = W + ma
the weight of a body is
W = m g
Let's replace
T = m g + ma
T = m (g + a)
let's calculate
T = 50 (9.8 + 0.8)
T = 530 N
To calculate the time we use
y = v₀t + ½ a t²
since the box starts from rest on the sole its initial velocity is zero
y = ½ a t2
t = √ 2y / a
let's calculate
t = √ (2 10 / 0.8)
t = 12.65 s
TRASLATE
Este es un ejercicio de la segunda ley de Newton,
T – W = m a
donde T es la tension del cable, W el peso y a la aceracion de la caja
T = W + ma
el pesode un cuerpo es
W = m g
Substituyamos
T = m g + ma
T = m ( g +a)
calculemos
T = 50 ( 9,8 + 0,8)
T = 530 N
Para calcular el tiempo usamos
y = v₀t + ½ a t²
como la caja parte del reposo en el suela su velocidad inicial es cero
y= ½ a t²
t= √ 2y/a
calculemos
t = √ (2 10/0,8)
t = 12,65 s
Answer:
In the case of the blackish-yellow powder, the black color is due to the presence of a iron and yellow color is due to sulfur. As the iron has retained its original properties it has got attached to the magnet. Thus the blackish-yellow powder is considered a mixture.
Explanation:
mark me brainliest
Answer:
0 degrees
Explanation:
Let
are two forces. The resultant of two forces acting on the same point is given by :

Where
is the angle between two forces
When
i.e. when two forces are parallel to each other,


When
i.e. when two forces are parallel to each other,


When
i.e. when two forces are parallel to each other,


It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.
Answer:four times
Explanation:
Given
mass of both cars A and B are same suppose m
but velocity of car B is same as of car A
Suppose velocity of car A is u
Velocity of car B is 2 u
A constant force is applied on both the cars such that they come to rest by travelling certain distance
using to find the distance traveled
where, v=final velocity
u=initial velocity
a=acceleration(offered by force)
s=displacement
final velocity is zero
For car A


For car B


divide 1 and 2 we get

thus 
distance traveled by car B is four time of car A
To the Earth in less than ten minutes.