Answer:
<em>The velocity after the collision is 2.82 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
![P=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=P%3Dm_1v_1%2Bm_2v_2)
If a collision occurs and the velocities change to v', the final momentum is:
![P'=m_1v'_1+m_2v'_2](https://tex.z-dn.net/?f=P%27%3Dm_1v%27_1%2Bm_2v%27_2)
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
![m_1v_1+m_2v_2=m_1v'_1+m_2v'_2](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3Dm_1v%27_1%2Bm_2v%27_2)
If both masses stick together after the collision at a common speed v', then:
![m_1v_1+m_2v_2=(m_1+m_2)v'](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3D%28m_1%2Bm_2%29v%27)
The common velocity after this situation is:
![\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%27%3D%5Cfrac%7Bm_1v_1%2Bm_2v_2%7D%7Bm_1%2Bm_2%7D)
There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.
After the collision, both cars stick together. Let's compute the common speed after that:
![\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%27%3D%5Cfrac%7B3.91%2A5.7%2B4%2A0%7D%7B3.91%2B4%7D)
![\displaystyle v'=\frac{22.287}{7.91}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%27%3D%5Cfrac%7B22.287%7D%7B7.91%7D)
![\boxed{v' = 2.82\ m/s}](https://tex.z-dn.net/?f=%5Cboxed%7Bv%27%20%3D%202.82%5C%20m%2Fs%7D)
The velocity after the collision is 2.82 m/s
Answer:
A - Crest, B - amplitude, C - wavelength, D - trough
Explanation:
Answer:
The distance traveled by the woman is 34.1m
Explanation:
Given
The initial height of the cliff
yo = 45m final, positition y = 0m bottom of the cliff
y = yo + ut -1/2gt²
u = 20.0m/s initial speed
g = 9.80m/s²
0 = 45.0 + 20×t –1/2×9.8×t²
0 = 45 +20t –4.9t²
Solving quadratically or by using a calculator,
t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s
So this is the total time it takes for the ball to reach the ground from the height it was thrown.
The distance traveled by the woman is
s = vt
Given the speed of the woman v = 6.00m/s
Therefore
s = 6.00×5.69 = 34.14m
Approximately 34.1m to 3 significant figures.
Answer:
The answer is 4N or B
Explanation:
Just the equation W = F x D.
We have W = 8 J and D = 2 m using algebra ....
8J/2m = F ... F = 4.