data which is expressed in form of following way
![a = a_o + \Delta a](https://tex.z-dn.net/?f=a%20%3D%20a_o%20%2B%20%5CDelta%20a)
here in above expression
= true value
= uncertainty in the value
now the relative uncertainty is given as
![\frac{\Delta a}{a_o}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20a%7D%7Ba_o%7D)
now by above formula we can say
a) 2.70 ± 0.05cm
here
True value = 2.70
uncertainty = 0.05
Relative uncertainty =
= 0.0185
b) 12.02 ± 0.08cm
here
True value = 12.02
uncertainty = 0.08
Relative uncertainty =
= 0.00665
As we know that the formula of kinetic energy will be
![KE = \frac{1}{2} mv^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E2)
now here we know that
m = 2 kg
v = 1 m/s
so from the above equation we have
![KE = \frac{1}{2}(2)(1^2)](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%282%29%281%5E2%29)
![KE = 1 J](https://tex.z-dn.net/?f=KE%20%3D%201%20J)
Here you go it was too long to type
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Answer: C. 39 s
Explanation:
We know the constant speed is 0.22 m/s. We have to get to 8.5 m. We divide <u>8.5 m by 0.22</u> = 38.6. After we estimate, 6 is greater than 5, so 39 s.