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amm1812
4 years ago
7

1. Transverse waves _____.

Physics
2 answers:
poizon [28]4 years ago
8 0
D. have particle moment perpendicular to the direction of the energy.
kumpel [21]4 years ago
7 0
The answer is D to you question 
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I know this is easy but i’m am just not sure
Alex

Answer:

kinetic energy

Explanation:

vinegar and baking soda are composed of atoms which react to each other when mixed therefore they convert the potential energy inti kinetic energy.

7 0
3 years ago
A long string is pulled so that the tension in it increases by a factor of four. If the change in length is negligible, by what
rusak2 [61]

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

v = \sqrt{\frac{T}{\mu}}

Here

v = Wave speed

T = Tension

\mu = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

v \propto \sqrt{T}

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

v \propto \sqrt{4} = 2  

The factor that the wave speed change is 2.

3 0
3 years ago
What type of wave can be seen by the human eye
Svetach [21]
Light can be seen by the human eye
3 0
4 years ago
Read 2 more answers
Un recipiente con una capacidad de 25L contiene un gas a una presión de 7,5 atm. Calcula la nueva presión a la que se verá somet
amid [387]

Responder:  

18.75 atmósferas  

Explicación:  

Paso uno:  

datos dados

volumen inicial V1 = 25L

Presión inicial P1 = 7.5 atm

volumen final V2 = 10L

presión final P2 = ??

Segundo paso:

Aplicando la expresión de gas que relaciona el volumen y la presión, es decir

P1V1 = P2V2

sustituyendo nuestros datos tenemos

7.5 * 25 = P2 * 10

187.5 = P2 * 10

divide ambos lados por 10

P2 = 187.5 / 10

P2 = 18.75 atmósferas

<em><u>La presión final es de 18.75 atm.</u></em>

5 0
3 years ago
Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I
mezya [45]

The problem is basically asking us to find a way to find the sound intensity I, in terms dependent on the sound level and the reference intensity I_0.For this purpose we can start from the unit used in the scale logarithmic decibel, that is

\beta = 10log_{10}\frac{I}{I_0}

Where

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

Using the logarithmic properties of the exponents the above expression can be described as:

(\frac{I}{I_0})^{10} = 10^{\beta}

I = I_0 10^{\frac{\beta}{10}} \righarrow that is the expression or technique to find the intensity of sound.

8 0
3 years ago
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