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3 years ago

The graph indicates Linda’s walk.

Physics

2 answers:

Lyrx [107]3 years ago

7 0

Answer:

Linda started moving out and then stopped moving after 6 seconds

Explanation:

On the axes of the graph, one can see that the lower axis is labeled (time). Time can only move forward, thus the graph will forever continue leftwards.

The verticle axis is labeled (Position in (m)), this changes relative to the motion that Linda takes. As one can see, from (0) to (6) seconds Linda was moving forward, as her position in meters was increasing. however, at 6 seconds she stopped moving, thus the graph remained a horizontal line. Therefore, the answer is the following:

Linda started moving out and then stopped moving after 6 seconds.

tatuchka [14]3 years ago

6 0

Answer:

Explanation:

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The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as

$Qo=1.6 \times 10^{2} \mathrm{~mL}$

<h3>What is the water outflow in 30 secs through 200 mm of the capillary tube?</h3>

$\begin{aligned}\Delta P &=6660 \mathrm{~m} / \mathrm{m}^{2} \\\mu &=8.01 \times 10^{-4} \text { Pas } \\t &=30 \mathrm{~s} \\L &=200 \mathrm{~mm}=200 \times 10^{-3} \mathrm{~m} \\D &=1.5 \mathrm{~mm}=1.5 \times 10^{-3} \mathrm{~m} \Rightarrow \gamma=\frac{1.5 \times 10^{-3}}{2} \mathrm{~m}\end{aligned}$

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$Q=\frac{\pi \times\left(\frac{1.5 \times 10^{-3}}{2}\right)^{4} \times 6660}{8 \times 8.01 \times 10^{-4} \times 200 \times 10^{-3}}$

$Q=5.2 \mathrm{~mL} / \mathrm{s}$

In $30s the quantity that flows out of the tube

$&Qo=5.2 \times 30 \\&Qo=1.6 \times 10^{2} \mathrm{~mL}$

In conclusion, the quantity that flows out of the tube

$Qo=1.6 \times 10^{2} \mathrm{~mL}$

Read more about the flows rate

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A rotating viscometer consists of two concentric cylinders –an inner cylinder of radius Rirotating at angular velocity (rotation

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Answer:

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