A 2.6 kg mass attached to a light string rotates on a horizontal,
1 answer:
The maximum speed the mass can have before it breaks is 2.27 m/s.
The given parameters:
- <em>maximum mass the string can support before breaking, m = 17.9 kg</em>
- <em>radius of the circle, r = 0.525 m</em>
The maximum speed the mass can have before it breaks is calculated as follows;
Thus, the maximum speed the mass can have before it breaks is 2.27 m/s.
Learn more about maximum speed of horizontal circle here:brainly.com/question/21971127
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Answer:
θ = sin⁻¹
Explanation:
From one of the equations of motion, v² = u² + 2as.......... equation 1
Since the object thrown was moving against gravity, then the acceleration, a would change to -g and the initial velocity u would change to V₀ sin θ because the object is travelling at angle of θ to the horizontal. By inputting all these parameter into equation 1, we would arrive at:
v² = (u sin θ)² - 2gd
(u sin θ)² = 2gd
d = (u sin θ)²/2g
sin² θ = 2gd
sin θ =
θ = sin⁻¹
