A 2.6 kg mass attached to a light string rotates on a horizontal,
1 answer:
The maximum speed the mass can have before it breaks is 2.27 m/s.
The given parameters:
- <em>maximum mass the string can support before breaking, m = 17.9 kg</em>
- <em>radius of the circle, r = 0.525 m</em>
The maximum speed the mass can have before it breaks is calculated as follows;
Thus, the maximum speed the mass can have before it breaks is 2.27 m/s.
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Answer:
1408.685 KN/C
Explanation:
Given:
R = 0.45 m
σ = 175 μC/m²
P is located a distance a = 0.75 m
k = 8.99*10^9
- The Electric Field Strength E of a uniformly solid disk of charge at distance a perpendicular to disk is given by:
part a)
Electric Field strength at point P: a = 0.75 m
part b)
Since, R >> a, we can approximate a / R = 0 ,
Hence, E simplified relation becomes:
E = σ / 2*e_o
part c)
Since, a >> R, we can approximate. that the uniform disc of charge becomes a single point charge:
Electric Field strength due to point charge is:
E = k*δ*pi*R^2 / a^2
Since, R << a, Surface area = δ*pi
Hence,
E = (k*δ*pi/a^2)