Friction would inhibit your speed and maximum work potential so, friction is the answer.
Hope this helps, Brainliest please.
Answer:
How is high-speed internet typically transmitted around the world? over telephone wires b. through fiber optic cables c. beamed wirelessly to homes d via satellites
Explanation:
Answer:
0.51 m
Explanation:
Using the principle of conservation of energy, change in potential energy equals to the change in kinetic energy of the spring.
Kinetic energy, KE=½kx²
Where k is spring constant and x is the compression of spring
Potential energy, PE=mgh
Where g is acceleration due to gravity, h is height and m is mass
Equating KE=PE
mgh=½kx²
Making x the subject of formula
![x=\sqrt {\frac {2mgh}{k}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%20%7B%5Cfrac%20%7B2mgh%7D%7Bk%7D%7D)
Substituting 9.81 m/s² for g, 1300 kg for m, 10m for h and 1000000 for k then
![x=\sqrt \frac {2*1300*9.81*10}{1000000}=0.50503465227646m\\x\approx 0.51 m](https://tex.z-dn.net/?f=x%3D%5Csqrt%20%5Cfrac%20%7B2%2A1300%2A9.81%2A10%7D%7B1000000%7D%3D0.50503465227646m%5C%5Cx%5Capprox%200.51%20m)
Answer
given,
mass of the steel ball = 35 g = 0.035 kg
the horizontal distance is
( v cos θ ) t = 4.8..........(1)
the vertical distance is
...(2)
since,
![(v sin \theta )t = 4](https://tex.z-dn.net/?f=%28v%20sin%20%5Ctheta%20%29t%20%3D%204%20)
![\dfrac{1}{2}gt^2 = (v sin \theta) t - 1.2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7Dgt%5E2%20%3D%20%28v%20sin%20%5Ctheta%29%20t%20-%201.2)
..................(3)
using equation(2) and (3)
(v t)² (cos²θ+ sin²θ) = 4.8² + 4²
(v t)² = 39.04
![\dfrac{1}{2}gt^2 = 4 - 1.2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7Dgt%5E2%20%3D%204%20-%201.2)
![t = \sqrt{\dfrac{2(4-1.2)}{9.8}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cdfrac%7B2%284-1.2%29%7D%7B9.8%7D%7D)
t = 0.76 s
the speed is
vt = 6.25
v × 0.76 = 6.25
v = 8.22 m/s