It is , how close a measurement is to an accepted value for the measurement !
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Answer:
391.46 L
Explanation:
Given:
Initial temperature of the water = 23.4°C
Final temperature of the water = 39°C
Temperature change for the water, ΔT = (39 - 23.4) = 15.6°C
Heat absorbed by the water = 2.55 × 10⁴ kJ = 2.55 × 10⁷ J
Density of the water = 0.998 g/mL
Specific heat of the water, C = 4.184 J/g°C
Now,
The heat absorbed by the water, q = mCΔT
where, m is the mass of the water
Thus,
we have
2.55 × 10⁷ J = m × 4.184 × 15.6
or
m = 390682.45 grams
also,
Density = mass / volume
thus,
0.998 = 390682.45 / volume
or
Volume = 391465.38 mL
or
Volume = 391.46 L
Answer:
(a) 16500 grams
(b) 16500000 milligrams
(c) 16500000000 micrograms
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