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svetoff [14.1K]
3 years ago
6

The term used to describe the composition of an igneous rock rich in the elements magnesium and iron is

Chemistry
1 answer:
ZanzabumX [31]3 years ago
8 0
Mafic igneous rocks I believe
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During the process of photosynthesis, green implants produce
Advocard [28]
During photosynthesis, plants produce glucose from simple inorganic molecules - carbon dioxide and water - using light.
I think the answer is d— sugar.
7 0
3 years ago
Now examine salts containing the halide anions, cl- and br-. Most of these are soluble. What two cations listed lead to insolubl
tatiyna

Ag+ and Pb+2 are two cations that are suggested as producing insoluble halide salts when studying salts containing the halide anions, cl- and br-. First, the charge's number is provided.

Neutral binary salts, also referred to as halide salts, are mixtures of metals and non-metals. The non-metal behaves in a reduced oxidation state at all times. They are the outcome of mixing a hydroxide and hydracid. halide salts of haloids are produced by the reaction of a hydroxide and a hydracid.

Ions are cations with positive charges. They emerge when the electrons of an elemental metal are lost. However, they don't lose any protons; they only lose one or more electrons. To denote a cation, the charge is superscripted following the element name or chemical formula.

Learn more about halide salts here

brainly.com/question/20815131

#SPJ4

8 0
1 year ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
A dull metal object has a density of 8.8 G/ML and a volume of 20 ML calculate the mass
Alex

Answer:

Mass = 0.000176 gram

Steps:

m =  V × ρ

=  20 milliliter × 8.8 gram/cubic meter

=  2.0E-5 cubic meter × 8.8 gram/cubic meter

=  0.000176 gram

Explanation:

8 0
3 years ago
Balance the equation below and use it to answer this question:
Svet_ta [14]

Answer:

2H2 + O2 -----> 2H2O

Not sure about the second question though.

8 0
3 years ago
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