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umka21 [38]
3 years ago
7

A runner is jogging in a straight line at a

Physics
1 answer:
murzikaleks [220]3 years ago
4 0

Explanation:

The runner was 8.6km away from the finish line when the bird starts flying.

Therefore it takes the bird 8.6/14.4 = 0.60 hours for the bird to fly to the finish line.

In that 0.60 hours, the runner would have ran an extra 3.6km/h * 0.6h = 2.16km.

Now, the runner and the bird are flying towards each other. The distance between them is 8.6 - 2.16 = 6.44km and their combined speed is 18.0km.

Hence, they will meet in 6.44/18.0 = 0.36 hours.

Overall, the bird flew for 0.60 + 0.36 = 0.96 hours, and flew 14.4km/h * 0.96h = 13.8km.

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A small racquet ball launcher is set up 5 meters from a 12 meter tall wall. It launches a racket ball at 30 m/s at an angle of 4
Strike441 [17]

Answer:20.82 m

Explanation:

Given

distance between wall and launcher=5 m

initial velocity=30 m/s

Launching angle=45^{\circ}

Height of wall=12 m

maximum height by ball

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{30^2sin^{2}45}{2\times 9.8}

h=22.95 m

y=xtan\theta -\frac{gx^2}{2u^2cos^\theta }

y=4.72 m

so ball will strike with wall

and for perfect restitution final velocity of ball will be same as the horizontal velocity before its impact, only direction will be opposite and vertical velocity will be zero

thus it seems as if someone throw the ball with horizontal velocity of 30cos45 from a height of 4.72

Time required to cover 4.72 m

t=\sqrt{\frac{2h}{g}}

t=\sqrt{\frac{9.45}{9.8}}

t=0.981 s

Horizontal distance traveled in this time

R=ucos45\times t

R=30\times cos45\times 0.981

R=20.82 m

6 0
3 years ago
A flat screen is located 0.55 m away from a single slit. Light with a wavelength of 544 nm (in vacuum) shines through the slit a
kobusy [5.1K]

Answer:

Explanation:

The diffraction pattern is given as

Sinθ = mλ/ω

Where m=1,2,3,4....

Now, when m=1

Sinθ = λ/ω

Then,

ω = λ/Sinθ

The width of the central bright fringe is given as

y=2Ltanθ. From trigonometric

Then,

θ=arctan(y/2L)

Given that,

y=0.052m

L=0.55m

θ=arctan(0.052/2×0.55)

θ=arctan(0.0473)

θ=2.71°

Substituting this into

ω = λ/Sinθ

Since λ=544nm=544×10^-9m

Then,

ω = 544×10^-9/Si.2.71

ω = 1.15×10^-5m.

5 0
3 years ago
Astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is toda
disa [49]

Answer:

First, as you may know, the light travels at a given velocity.

In vaccum, this velocity is c = 3x10^8 m/s.

And we know that:

distance = velocity*time

Now, if some object (like a star ) is really far away, the light that comes from that star may take years to reach the Earth.

This means that the images that the astronomers see today, actually happened years and years ago (So the night sky is like a picture of the "past" of the universe)

Also, for example, if an astronomer sees some particular thing, he can apply a model (a "simplification" of some phenomena that is used to simplify it an explain it) and with the model, the scientist can infer the information of the given thing some time before it was seen.

8 0
3 years ago
A ball is moving at 4.5 m/s and has a momentum of 75 kg·m/s. What is the ball's mass?
chubhunter [2.5K]

Answer:

Mass = 16.67kg

Explanation:

Given the following data;

Velocity = 4.5m/s

Momentum = 75kgm/s

To find the mass;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

Substituting into the equation, we have

75 = mass * 4.5

Mass = 75/4.5

Mass = 16.67kg

Therefore, the ball's mass is 16.67 kilograms.

5 0
3 years ago
How does molten rock and gas leave the volcano
9966 [12]
The vent the opening through which molten rock and gas leave a volcano
4 0
4 years ago
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