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Natalka [10]
3 years ago
6

30) When you press a piano key, a hammer strikes a very tight cable to produce a clear tone. How does the cable that produces a

low note compare to one the produces a high note?
a) (A) The low note cable is thinner or shorter than the high note cable.
b) (B) The low note cable is longer or thicker than the high note cable.
c) (C) The cables are the same, but the hammer that produces the low note is heavier.
d) (D) The cables are the same, but the hammer that produces the low note is lighter.
Physics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

Remember: in physics and music, frequency equates to pitch, and amplitude equates to loudness. Also, remember frequency is inversely proportional to wavelength- remember this!

Thus, (B) should be the correct answer, because, think about it,  if a note is higher, than the wavelength should be shorter so the length should also be shorter, but in the case of B, if the cable is longer or thicker then the wavelength gets longer. Therefore, going from low to high, the string should be getting shorter, due to the fact that as wavelength gets shorter, frequency gets higher.

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I got you

Explanation:

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I hope this helps you

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2 years ago
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lianna [129]
<h2>Answer:</h2>

<em><u>Velocity of throwing arrow = 43.13 m/s.</u></em>

<h2>Explanation:</h2>

In the question,

Let us say the height from which the arrow was shot = h

Distance traveled by the arrow in horizontal = 61 m

Angle made by the arrow with the ground = 2°

So,

From the <u>equations of the motion</u>,

61 =u.t\\t=\frac{61}{u}

Now,

Also,

Finally, the angle made is 2 degrees with the horizontal.

So,

Final horizontal velocity = v.cos20°

Final vertical velocity = v.sin20°

Now,

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Also,

v=u+at\\vsin20=0+9.8(t)\\t=\frac{v.sin20}{9.8}

So,

We can say that,

\frac{v.sin20}{9.8}=\frac{61}{v.cos20}\\v^{2}.sin20.cos20=597.8\\v^{2}=1860.56\\v=43.13\,m/s

<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>

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50 N

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