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fiasKO [112]
3 years ago
12

shelly starts from rest on her bicycle at the top of a hill. After 6.0s she has reached a final velocity of 14m/s. what is shell

ys acceleration.
Physics
2 answers:
earnstyle [38]3 years ago
8 0
Divide 14 by 6 and there is your answer with the unit of m
Anna007 [38]3 years ago
7 0

Answer:

Acceleration, a=2.33\ m/s^2

Explanation:

It is given that,

Initial speed of Shelly, u = 0

After 6 seconds, she has reached a final velocity of 14 m/s, v = 14 m/s

We need to find the acceleration of Shelly. The formula to find the acceleration is given by :

a=\dfrac{v-u}{t}

a=\dfrac{14\ m/s-0}{6\ s}

a=2.33\ m/s^2

So, the acceleration of Shelly's is 2.33\ m/s^2. Hence, this is the required solution.

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To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as

Buoyancy force

F_B = V\rho g

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V = Volume

\rho=Density of air

g = Acceleration due to gravity

Weight

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m = mass

g = Gravity

Our values are given as,

\text{Weight of the sphere} = W = 0.34 N

\text{Volume} = V = 13 cm^3 = 13*10^{-6}m^3

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\text{gravity}= g = 9.8 m/s^2

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F = V\rho g

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