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valkas [14]
2 years ago
12

What is the net force and acceleration of a ball of mass 0.750 kilograms that is subjected to forces of 11.00 newtons and 7.00 n

ewtons from opposite directions?
Physics
1 answer:
madam [21]2 years ago
4 0
M = 0.75kg
F1 = 11N
F2 = 7N

Because forces are in opposite direction, the ball will accelerate in direction of force that has bigger amplitude. 

F = m*a
a = F/m
a = (F1-F2)/m
a = 5.333 m/s^2
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Answer:

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and         \frac{\delta \eta }{\delta r} =  \frac{\pi}{8} *  \frac{4* Pr^3}{v}

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             \Delta  \eta  = \frac{\pi}{8} [ |\frac{r^4}{v}  | *  \Delta  P   +    | \frac{4 *  P * r^3}{v}  |*  \Delta  r +  |-\frac{P* r^4}{v^2}  |*  \Delta  v]

substituting values

            \Delta  \eta  = \frac{\pi}{8} [ |\frac{(0.002)^4}{0.5*10^{-9}}  | *  1750   +    | \frac{4 *  4 *10^{5} * (0.002)^3}{0.5*10^{-9}}  |*  0.0002 +  |-\frac{ 4*10^{5}* (0.002)^4}{(0.5*10^{-9})^2}  |*  0 ]

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