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ivolga24 [154]
2 years ago
15

Which type of mixture is it, if the solid settles out of the mixture over time?.

Physics
1 answer:
Elanso [62]2 years ago
6 0

Answer:

Suspension

Explanation:

--

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Write this number in standard notation. 4.702 x 10–4
sergeinik [125]

Answer:

0.0004702

Explanation:

5 0
3 years ago
Can the validity of a model be limited, or must it be universally valid? How does this compare to the required validity of a the
Vilka [71]

The model is based on hypothesis  to get an initial idea for analyzing a complex problem. Hence, the validity of a model is limited and may not be valid universally. On the other hand, theories and laws are confirmed hypothesis which are universally valid. These are formulated after repeated testings. theories are more explanatory.

7 0
3 years ago
A sample contains 16 g of a radioactive isotope. how much radioactive
mafiozo [28]

After one half-life, 8 g of radioactive isotope will remain in the sample.

<h3>What is radioactivity?</h3>

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.

The following formula is used to compute the number of half lives elapsed:

\rm N=\frac{N_0}{2^n} \\\\ N=\frac{16}{2} \\\\ N= 8 \ gram

Hence,8 gram of radioactive isotope remains in the sample after 1 half-life.

To learn more about the radioactivity, refer  to the link;

brainly.com/question/1770619

#SPJ1

7 0
2 years ago
Read 2 more answers
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6
lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

I = \frac{P_{avg}}{A}

I = \frac{P_{avg}}{4\pi r^2}

I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m

I = 6.529*10^{-6}W/m^2

The amplitude of electric field at the receiver is

I = \frac{E_{max}^2}{2\mu_0 c}

E_{max}= \sqrt{2I\mu_0 c}

The amplitude of induced emf by this signal between the ends of the receiving antenna is

\epsilon_{max} = E_{max} d

\epsilon_{max} = \sqrt{2I \mu_0 cd}

Here,

I = Current

\mu_0 = Permeability at free space

c = Light speed

d = Distance

Replacing,

\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}

\epsilon_{max} = 0.05434V

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0
4 years ago
while playing her guitar , karen plucks one string with increasin levels of force. what effect does this have on the sound produ
kirza4 [7]
The sound will get louder.
3 0
3 years ago
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