Answer:
v = 10.47 m/s
a = 219.32 m/s²
Explanation:
The velocity of the stone can be given by the following formula:
v = r ω
where,
v = linear velocity of the stone = ?
r = radius of tire = 0.5 m
ω = angular velocity = (200 rev/min)(2π rad/1 rev)(1 min/60 s) = 20.94 rad/s
Therefore,
v = (0.5 m)(20.94 rad/s)
<u>v = 10.47 m/s</u>
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The acceleration of the stone will be equal to the centripetal acceleration. Therefore,
a = v²/r
a = (10.47 m/s)²/0.5 m
<u>a = 219.32 m/s²</u>
Three significant figures in the number 103
<span>The measure of an acute angle is between 0 degrees and 90 degrees. It must be smaller than the perpendicular angle i.e., 90 degree. So, the answer of your question would be false.
In short, Your Answer would be "False"
Hope this helps!</span>
Answer:
V = 0.32 m /s
Explanation:
Momentum of the man on the sledge along with sledge
= (80+8) x 10 = 880 kg. m/s When the man jumps off the sledge , the velocity of the sledge will remain intact at 10 m/s
When the sledge hits the boulder and bounces back the momentum of the sledge - boulder system will remain conserved .
change in momentum of sledge = 8 x (10 +6 )
= 128 kg m/s
Change in the momentum of boulder
= 400 V -0
= 400V
400V = 128
V = 0.32 m /s
