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Ivahew [28]
3 years ago
8

A six row combin harvests 266 pounds of corn per min. How many bushels of corn does it harvest per hour? (Note: 1 Bu = 56 Lbs) R

ound to the nearest Whole Number.
Chemistry
1 answer:
kiruha [24]3 years ago
5 0

Answer:

The six-row combin harvests 285 bushels of corn per hour.

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three.

If the relationship between the magnitudes is direct, you can apply the following formula:

a ⇒ b

c ⇒ x

So: x=\frac{a*b}{c}

In this case you can apply it in the following way: if 56 pounds is equal to 1 bushel, 266 pounds to how many bushels is it?

x=\frac{266 pounds*1 bushel}{56 pounds}

x=4.75

This is, a six row combin harvests 4.75 bushels of corn per min.

So, being 1 hour equal to 60 minutes, you can apply the following rule of three: if in 1 minute a six-row harvester harvests , in 60 minutes how many bushels of corn it harvests?

bushels of corn=\frac{60 minutes*4.75 bushels of corn}{1minute}

bushels of corn=  285

<u><em> The six-row combin harvests 285 bushels of corn per hour.</em></u>

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evablogger [386]

If 28.4 g of HgO decomposes and produces 2.0 g of oxygen, then 26 grams of Hg is produced.

<h3>What is decomposition reaction?</h3>

Decomposition reactions occur when complex chemical entities split apart into smaller components. Decomposition reactions often demand energy input.

There are three different kinds of breakdown reactions: thermal, photolytic, and electrolytic.

Mass_{reactant = Mass_{product}

Mass_{mercury oxide = Mass_{mercury} + mass_{oxygen}

28g =        mass_{mercury} + 2g

   mass_{mercury} = 26g

Thus, 28.4 g of HgO decomposes and produces 2.0 g of oxygen, then 26 grams of Hg is produced.

percentage mass_{mercury} = \frac{mass_{mercury}}{mass_{mercury}oxide}  X 100%

= 26g/28g

= 93%

thus  93% is the percent by mass of Hg present in HgO.

To learn more about Decomposition reaction, refer to the below link:

brainly.com/question/14112196

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4 0
1 year ago
If 0.0262 mol of cacl2 is dissolved in water to make a 0.520 m solution, what is the volume of the solution?
Oduvanchick [21]
Cacl2  dissolve   in  water   according  to the  following  equation

Cacl2 + H2O  =  Ca(OH) + Hcl
Volume=  moles/molarity
  The  reacting  ratio    between CaCl2  to  Ca(OH)  is   1:1
therefore  moles  of  solution   is  also  0.0262  moles hence  volume   is  =
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5 0
3 years ago
Be sure to answer all parts. What is the effect of each of the following on the volume of 1 mol of an ideal gas? (a) The pressur
aksik [14]

Answer

A)The volume decreases by a factor of 4

B), the volume has increased by factor of 2

Explanation:

A)Given:

P1= 760Kpa

P2 =202Kpa

The temperature changes from37C to155C

There is increase In pressure from P1 to P2

P1= 760torr.

We need to convert to Kpa

But, 1atm= 760torr

Then 760torr 101000pa

Then 101000pa = 101Kpa

We need to convert the temperature from Celsius to Kelvin

T1= 37+273= 310K

But from ideal gas, we know that PV = nRT where nR is constant

Where P= pressure

V= volume

T= temperature

n = number of moles

(P1V1/T1)=(P2V2/T2)

V1/V2 = P2/P1 * T1/T2

V1/V2 = (202/101)*(310/155)

V1/V2=4

V2= V1/4

Therefore, the volume has decreased by factor of 4

B)

Given:

P1= 2atm

P2 =101Kpa

The temperature changes from 305K to 32C

There is increase In pressure from P1 to P2

P1= 2atm

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But, 1atm= 760torr

Then 760torr 101000pa

Then 101000pa = 101Kpa

P1= 202.65kpa

We need to convert the temperature from Celsius to Kelvin

T2= 32+273= 305K

But from ideal gas, we know that PV = nRT

Where P= pressure

V= volume

T= temperature

n = number of moles

(P1V1/T1)=(P2V2/T2)

V1/V2 = P2/P1 * T1/T2

V1/V2 = (202/101)

V1/V2 = (101/202.65)*(305/305)

V1/V2 = 1/2

V2=2V1

Therefore, the volume has increased by factor of 2

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