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Karo-lina-s [1.5K]
3 years ago
6

Many portable gas heaters and grills use propane, C3H8.

Chemistry
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

503.5 kJ

Explanation:

The combustion of reaction of propane, C3H8, is:

C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l)

The enthalpy of the reaction can be calculated by the enthalpy of formation of the substances, which is the enthalpy of the reaction that produces the substances by only its constituents. The values can be found at a thermodynamic table. The standard condition is 25°C and 1 atm, so:

H°f, C3H8(g) = -103.85 kJ/mol

H°f, O2(g) = 0

H°f, CO2(g) = -393.51 kJ/mol

H°f, H2O(l) = -285.83 kJ/mol

So, the enthalpy of the reaction is:

ΔH°rxn = ∑n*H°f products - ∑n*H°f reactants, where n is the coefficient of the substance:

ΔH°rxn = [3*(-393.51) + 4*(-285.83)] - (-103.85)

ΔH°rxn = -2220 kJ/ mol of C3H8

The heat produced is the value of the enthalpy multiplied by the number of moles of the fuel. The molar mass of C3H8 is 44.10 g/mol, so, in 10.0 g:

n = 10.0/44.10

n = 0.2268 mol

So, the heat is:

Q = -2220 * 0.2268

Q = -503.5 kJ

The minus signal indicates that the heat is being lost, so 503.5 kJ of heat is produced.

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How many grams of KCN are in 10.0 ml of a 0.10 M solution?
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Explanation:

As it is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{no. of moles}{Volume in liter}

As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.

Hence, putting these values into the above formula as follows.

                  Molarity = \frac{no. of moles}{Volume in liter}

                  0.10 M = \frac{no. of moles}{0.01 L}

                        no. of moles = 0.001 mol

As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.

                 No. of moles = \frac{mass}{molar mass}

                                 0.001 mol = \frac{mass}{65.12 g/mol}

                                 mass = 0.06152 g

Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.

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