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Virty [35]
3 years ago
6

The design of a new computer processor requires that electric current be carefully controlled. Why might an engineer want to use

a metalloid when designing a new computer processor?
A.) Metalloids are amphoteric.


B.) Metalloids are semiconductors.

C.) Metalloids are brittle.

D.) Metalloids are shiny.


_________________________________________________________

Which lists the elements in order from least conductive to most conductive?

A.) nitrogen (N), antimony (Sb), bismuth (Bi)

B.) nitrogen (N), bismuth (Bi), antimony (Sb)

C.) antimony (Sb), nitrogen (N), bismuth (Bi)

D)bismuth (Bi), antimony (Sb), nitrogen (N)
________________________________________________________

Which lists the elements in order from most conductive to least conductive?

A.) potassium (K), selenium (Se), germanium (Ge)

B.) germanium (Ge), potassium (K), selenium (Se)

C.) selenium (Se), germanium (Ge), potassium (K)

D.) potassium (K), germanium (Ge), selenium (Se)
Physics
2 answers:
sveticcg [70]3 years ago
8 0
B) They want the electric current to be carefully controlled so they use a metalloid as a semiconductor.

<span>D)bismuth (Bi), antimony (Sb), nitrogen (N) because of the number of free electrons in the lattice.

</span><span>C.) selenium (Se), germanium (Ge), potassium (K)
</span>again because of the free electrons in the lattice.

Hope this helps.
Reptile [31]3 years ago
7 0

Correct answer choice for question 1 is :


B.) Metalloids are semiconductors.


Explanation:


The form, design, and implementation of CPUs have replaced over the track of their past, but their primary process continues almost constant. Principal parts of a CPU involve the arithmetic logic unit (ALU) that executes arithmetic and logic operations, processor registers that provide operands to the ALU and save the results of ALU operations and a control unit that organizes the fetching and performance of directions by directing the coordinated operations of the ALU, registers and other elements.

____________________________________________________________


Correct answer choice for question 2 is :


D) Bismuth (Bi), antimony (Sb), nitrogen (N) because of the number of free electrons in the lattice.


Explanation:


The most conductive of all metals are silver, copper, and gold in that order. Silver is also the common thermally conductive component, and the maximum light reflecting component. Silver also has the unique feature that the tarnish that develops on silver is still extremely electrically conductive. Silver also has the greatest thermal conductivity of any component and the leading light reflectance.

____________________________________________________________

Correct answer choice for question 3 is :


C) Selenium (Se), germanium (Ge), potassium (K)

again because of the free electrons in the lattice.


Explanation:


The most highly conductive metals are silver, copper, and gold. Copper is highly conductive and commonly used in metal cables. Brass includes copper but other materials in its makeup decrease conductivity. Pure silver is the most conductive of all metals. Metals always have free electrons, that's what gives them a good conductor of electricity. Stainless steel may be the least conductive metal, but it still does carry electricity more efficiently than many other matters. In case, below normal circumstances, no material is completely non-conductive.

____________________________________________________________

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sleet_krkn [62]
Ruby, a variety of the mineral corundum is in the trigonal crystal system, with hexagonal scalenohedra crystals
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3 years ago
A sound wave, generated at a frequency of 440 hertz has a wavelength of 2.3 meters as it travels through a solid material. The a
Jlenok [28]

The approximate speed of the sound wave traveling through the solid material is 1012m/s.

<h3>Wavelength, Frequency and Speed</h3>

Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

From the wavelength, frequency and speed relation,

λ = v ÷ f

Where λ is wavelength, v is velocity/speed and f is frequency.

Given the data in the question;

  • Frequency of sound wave f = 440Hz = 440s⁻¹
  • Wavelength of the wave λ = 2.3m
  • Speed of the wave v = ?

To determine the approximate speed of the wave, we substitute our given values into the expression above.

λ = v ÷ f

2.3m = v ÷ 440s⁻¹

v = 2.3m × 440s⁻¹

v = 1012ms⁻¹

v = 1012m/s

Therefore, the approximate speed of the sound wave traveling through the solid material is 1012m/s.

Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701

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2 years ago
What type of motion occurs when an object spins around an axis without altering its linear position?
dimulka [17.4K]
That would be only rotational motion
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What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport
ad-work [718]

Answer: 1.13(10)^{3} Pa

Explanation:

This problem can be solved by the following equation:

\Delta P=\frac{8 \eta L Q}{\pi r^{4}}

Where:

\Delta P is the pressure difference between the two ends of the pipe

\eta=0.20 Pa.s is the viscosity of oil

L=2.6 km=2600 m is the length of the pipe

Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s} is the Rate of flow of the fluid

d=36 cm=0.36 m is the diameter of the pipe

r=\frac{d}{2}=0.18 m is the radius of the pipe

Soving for \Delta P:

\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}

Finally:

\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa

7 0
3 years ago
A proton and an alpha particle are momentarily at rest at adistance r from each other. They then begin to move apart.Find the sp
Arte-miy333 [17]

Answer:

The unknown quantities are:

E and F

The final velocity of the proton is:

√(8/3) k e^2/(m*r)

Explanation:

Hello!

We can solve this problem using conservation of energy and momentum.

Since both particles are at rest at the beginning, the initial energy and momentum are:

Ei = k (q1q2)/r

pi = 0

where k is the coulomb constant (= 8.987×10⁹ N·m²/C²)

and q1 = e and q2 = 2e

When the distance between the particles doubles, the energy and momentum are:

Ef = k (q1q2)/2r + (1/2)m1v1^2 + (1/2)m2v2^2

pf = m1v1 + m2v2

with m1 = m,   m2 = 4m,    v1=vf_p,    v2 = vf_alpha

The conservation momentum states that:

pi = pf      

Therefore:

m1v1 + m2v2 = 0

That is:

v2 = (1/4) v1

The conservation of energy states that:

Ei = Ef

Therefore:

k (q1q2)/r = k (q1q2)/2r + (1/2)m1v1^2 + (1/2)m2v2^2

Replacing

      m1 =  m, m2 = 4m, q1 = e, q2 = 2e

      and   v2 = (1/4)v1

We get:

(1/2)mv1^2 = k e^2/r + (1/2)4m(v1/4)^2 =  k e^2/r + (1/8)mv1^2

(3/8) mv1^2 = k e^2/r

v1^2 = (8/3) k e^2/(m*r)

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