Acceleration = v2 - v1 / t
a = 80 - 40 / 2
a = 40 / 2
a = 20 m/s²
In short, Your Answer would be 20 m/s²
Hope this helps!
True
I hope this helps and have a wonderful day filled with joy!!
Answer:
6.8 m/s2
Explanation:
Let g = 9.8 m/s2. The total weight of both the rope and the mouse-robot is
W = Mg + mg = 1*9.8 + 2*9.8 = 29.4 N
For the rope to fails, the robot must act a force on the rope with an additional magnitude of 43 - 29.4 = 13.6 N. This force is generated by the robot itself when it's pulling itself up at an acceleration of
a = F/m = 13.6 / 2 = 6.8 m/s2
So the minimum magnitude of the acceleration would be 6.8 m/s2 for the rope to fail
From my understanding, the two are opposite. Let me give you each word and what it scientifically means to me.
repetition
occurs when an activity is repeated by the same person
replication
occurs when an activity is repeated by a different person
I hope this completely answers your question! If you need further explanation, please let me know!
~Brooke❤️
We know that P = hρg
Where:
P - pressure Pa,
h - height in meter,
ρ – would be the density in kg / m^3; and
g - acceleration due to gravity is m / s^2
p = hρg if h = 0.735 meter, ρ = 13600 kg / meter^3, g = 10 meter/ sec^2
p = 0.735*13600*10 = 99960 Pa or
P = 1 x 10^5 Pa
Now with sea water if we have to make a barometer:
ρ = 1100 kg / meter^3 (given)
P = hρg if we put the value of P calculated and the value of ρ = 1100 kg /
meter^3 given, we will
get, 1 x 10^5 = h*1100*10
therefore, h = 9.09 meter or 29.82 feet of water.
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