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MatroZZZ [7]
2 years ago
8

The length of a logical record is fixed for a given operating system. a) true b) false

Physics
1 answer:
Nastasia [14]2 years ago
8 0
Answer:

False - An operating system should allow the user to specify the length of the physical record. If the input physical record is very large the operating system needs to know where one logical record ends and another begins.

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In a series lrc circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance,
taurus [48]

When you double capacitance and inductance, the new resonance frequency becomes f/2.

  • Resonance frequency:

The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.

It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.

Xc = Xl

which gives the value for resonance frequency:

f = \frac{1}{2\pi \sqrt{LC} }

where;

f is the resonance frequency

L is the inductance

C is the capacitance

When you double capacitance and inductance, the new resonance frequency becomes;

f' = \frac{1}{2\pi \sqrt{2L2C} }

f' = \frac{1}{2\pi \sqrt{4LC} }

f' = \frac{1}{\pi \sqrt{LC} }\frac{1}{2}

f' = \frac{1}{2} f

Thus from above,

When you double capacitance and inductance, the new resonance frequency becomes f/2.

Learn more about resonance frequency here:

<u>brainly.com/question/13040523</u>

#SPJ4

6 0
2 years ago
Identifying the guilty party was mainly based on eyewitness accounts during what time period?
kondaur [170]

The time period for guilty party was between 1900-1988.

8 0
3 years ago
Read 2 more answers
Helppppppppppp im dieing
Otrada [13]
It would be 1. B 2. A 3. A
7 0
3 years ago
A 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. Calculate the
kumpel [21]

The car’s momentum after 4.21s is 24617.4 kgm/s

<h3>Newton's Second Law of Motion.</h3>

Newton's second law state that, the rate of change of momentum, is directly proportional to the applied force.

Given that a 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. To calculate the car’s momentum after 4.21 s, Let us first list all the parameters involved.

  • Velocity u = 10.2 m/s
  • Acceleration a =  2.45 m/s²
  • Mass m = 1200Kg
  • Time t = 4.21 s

From Newton's second law,

F = (mv - mu) / t

ma = (mv - mu) / t

Substitute all the parameters into the formula above.

1200 × 2.45 = ( mv - 1200 × 10.2 ) / 4.21

2940 = ( mv - 12240 ) / 4.21

Cross multiply

12377.4 = mv - 12240

Make mv the subject of the formula

mv = 12377.4 + 12240

mv = 24617.4 kgm/s

Therefore, the car’s momentum after 4.21s is 24617.4 kgm/s

Learn more about Momentum here: brainly.com/question/25121535

#SPJ1

3 0
1 year ago
I really need help I don't understand on evaluate and on 14
Assoli18 [71]
Use the velocity formula
final velocity=intitial velocity+(acceleration x time)
plug the numbers into the equation
12=8+(a x 4)
a x 4=4
acceleration = 1 meter per second
Hope this helps.
4 0
3 years ago
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