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Irina18 [472]
3 years ago
6

Suppose the volume of a container is decreased, but the same number of gas molecules is present at the same temperature. What wi

ll happen to the molecules?
The molecules will increase in number.

The molecules will decrease in number.

There will be more molecules per unit volume.

There will be less molecules per unit volume.
Chemistry
1 answer:
charle [14.2K]3 years ago
6 0

Answer: Option (C) is the correct answer.

Explanation:

When the volume of a container is decreased and same number of gas molecules are present inside the container at the same temperature then it means that more number of gas molecules are spread per unit volume.

As earlier when the volume of container was more then the molecules were widely spread inside the container but on decreasing the volume of container, molecules come closer to each other and hence there will be increase in molecules per unit volume.  


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3 years ago
A certain half-reaction has a standard reduction potential +0.80 V . An engineer proposes using this half-reaction at the anode
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Answer:

a. Minimum 1.70 V

b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

ε⁰ cell = ε⁰ reduction -  ε⁰  oxidation

Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the  oxidized species  0.80 V, thus

ε⁰ reduction -  ε⁰  oxidation ≥  ε⁰ cell

Since ε⁰  oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V )  ≥  0.90 V

⇒ ε⁰ reduction  ≥ 1.70 V

Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

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What neutral element has 17 electrons an 18 neutrons?
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chlorine atom

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Explanation:

4 0
2 years ago
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Explanation:

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Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

                F_{net} = Buoyancy force(F_{b}) - weight force(w)

Also, buoyancy force (F_{b}) = (volume submerged in water × density of water) + (volume in oil × density of oil)

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It is given that density of graphite is 2.16 g/cm^{3} or 2160 kg/m^{3}.

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Thus, we can conclude that in the second weighing mass is 229.27 g.

5 0
3 years ago
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