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Irina18 [472]
3 years ago
6

Suppose the volume of a container is decreased, but the same number of gas molecules is present at the same temperature. What wi

ll happen to the molecules?
The molecules will increase in number.

The molecules will decrease in number.

There will be more molecules per unit volume.

There will be less molecules per unit volume.
Chemistry
1 answer:
charle [14.2K]3 years ago
6 0

Answer: Option (C) is the correct answer.

Explanation:

When the volume of a container is decreased and same number of gas molecules are present inside the container at the same temperature then it means that more number of gas molecules are spread per unit volume.

As earlier when the volume of container was more then the molecules were widely spread inside the container but on decreasing the volume of container, molecules come closer to each other and hence there will be increase in molecules per unit volume.  


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The letter “E” represents what
babunello [35]

Answer:

I think it stands for Energy, chemistry-wise.

Explanation:

(self-explanatory)

I hope this helps, have a nice day.

5 0
3 years ago
For the reaction given below, how many moles of nitrogen monoxide will form if we start with 2.0 moles of oxygen?
r-ruslan [8.4K]
<h3>Answer: 1.6 mol (option 5)</h3>

Explanation:

<u>Mole Ratio of O₂ : NO</u>

Based on the balanced equation, the mole ratio of O₂ : NO is 5 : 4

∴ for every mole of O₂ reacted, ⁴/₅ moles of NO is produced

<u>Moles of NO</u>

since the number of mol of O₂ =  2.0 mol

   then moles of NO produced = 2.0 mol × ⁴/₅

                                                   =  1.6 mol

∴ the moles of nitrogen monoxide that will form if we start with 2.0 moles of oxygen is 1.6 mol (option 5).

7 0
3 years ago
All matter has thermal energy because atoms are constantly
ololo11 [35]
The atoms are constantly in motion
3 0
3 years ago
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
4 years ago
A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
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