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SIZIF [17.4K]
3 years ago
12

Use the Periodic Table. Choose the correct electron configuration of carbon using the data shown in the electron configuration c

hart. 1s22s22p1 1s22s22p4 1s22s22p2 1s22s12p2
Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
6 0

Answer:

electron configuration of carbon: 1s²2s²2p²

Explanation:

The electron configuration of atoms (or ions) is depicted based on the Aufbau principle according to which electrons are added to various orbitals such that the orbital with the lowest energy gets occupied first followed by the next higher orbital.

The energy ordering of orbitals from the lowest to the highest is:

1s < 2s < 2p < 3s < 3p < 4s  < 3d ....

s orbitals can accommodate a maximum of 2 electrons

p orbitals = 6 electrons

d orbitals = 10 electrons

Now, the atomic number of carbon = 6

Since it is neutral, the atomic number = number of electrons = 6

Based on the Aufbau principle the electron configuration of C would be

1s²2s²2p²

AleksAgata [21]3 years ago
4 0

I think I have done a question like this before and i'm pretty sure your answer would be the 2nd one 1s22s22p4. I'm not 100% sure but try it at least.

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3 years ago
A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

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7 0
3 years ago
Nitroglycerin (c3h5n3o9) is a powerful explosive. its decomposition may be represented by 4c3h5n3o9 → 6n2 12co2 10h2o o2 this re
professor190 [17]
The balanced chemical reaction describing this decomposition is as follows:
<span>4c3h5n3o9 .............> 6N2 + 12CO2 +10H2O + O2

From the periodic table:
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mass of hydrogen = 1 gram
mass of carbon = 12 grams
Therefore:
mass of </span><span>C3H5N3O9 = 3(12) + 5(1) + 3(14) + 9(16) = 227 grams
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From the balanced chemical equation:
4(227) = 908 grams of </span>C3H5N3O9 produce 32 grams of O2. Therefore, to know the amount of oxygen produced from 4.5*10^2 grams <span>C3H5N3O9, all we need to do is cross multiplication as follows:
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7 0
3 years ago
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If 10.7 grams of NH4Cl is dissolved in enough water to make 800 mL of solution,what will be it's molarity
olga nikolaevna [1]
<h3><u>Answer;</u></h3>

Molarity = 0.25 M

<h3><u>Explanation;</u></h3>

Molarity is given by moles/Liter.

First we find moles:

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= (800mL)*(1L/1000mL) = 0.800L  

Therefore; molarity = 0.2moles/0.8L

                                = 0.25M

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