Answer:
The limiting reagents seemed to be those that were consumed first
.
Because when this reagent is consumed, the reaction stops. The quantity of this determines the total quantity of the product formed.
Explanation:
A limiting reagent is one that is consumed in its entirety. In this way, it delimits the amount of product that can be formed.
Take the case of two substances that interact and produce a chemical reaction. If one of the substances runs out as it is consumed during the process, the reaction will stop. The reagent consumed acts as a limiting reagent, that is, it limits the possibility of the reaction proceeding, and therefore it also limits the amount of the product generated by the reaction.
Answer:
If any atom has more electrons than one energy level can hold, then automatically the electron is accommodated in the next energy level (shell). The remaining extra electrons starts to fill the next energy level. This produces the valency of that particular atom.
Explanation:
Charge = number of proton - number of electron = 18-22 = -4
SO, OPTION A IS YOUR ANSWER........
Answer:
Electrical energy to mechanical energy
Explanation:
In an electric motor, the energy transformation that is involve is a move from from electrical energy to mechanical energy.
For every system, according to the law of conservation of energy "energy is neither created nor destroyed but transformed from one form to another".
- An electric motor converts electrical energy to mechanical energy
- The electrical energy passes through and electromagnet set up.
- This then cause the motion to rotate.
- Therefore, electrical energy is transformed to mechanical energy.
Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
