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max2010maxim [7]

3 years ago

5

What were the constraints on Nils Bohlin’s solution to safer seatbelts?

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

Answer:

He realized he needs to have the upper body and lower body held in place and needed the buckle as far down beside the person's hip so it could hold the body properly

Explanation: ''I realized both the upper and lower body must be held securely in place with one strap across the chest and one across the hips,'' Mr. Bohlin once said. ''The belt also needed an immovable anchorage point for the buckle as far down beside the occupant's hip, so it could hold the body properly during a collision.

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If anyone can get this question, 20 points for you!

torisob [31]

Answer:

Light

Explanation:

The discovery of light from the other side of a black hole was predicted by Einstein's theory of general relativity. ... The research began with a slightly different aim of a more common light formed by a black hole: the corona which wraps around the outside of it, formed as material falls in.

6 0

2 years ago

Use the balanced equation given below to solve the following problem; Calculate the volume in liters of CO produced by the react

Elan Coil [88]

Answer: 40.3 L

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Sb_2O_3=\frac{175g}{291.5g/mol}=0.600moles$

$Sb_2O_3+3C\rightarrow 2Sb+3CO$

According to stoichiometry :

1 moles of $Sb_2O_3$ produces = 3 moles of $CO$

Thus 0.600 moles of $Sb_2O_3$ will produce= $\frac{3}{1}\times 0.600=1.80moles$ of $CO$

Volume of $CO=moles\times {\text {Molar volume}}=1.80moles\times 22.4L/mol=40.3L$

Thus 40.3 L of CO is produced.

6 0

3 years ago

What is the name of this compound?<br><br> C6H6-<br> C=O-<br> H

ipn [44]

Answer: Benzaldahyde

Explanation: the C₆H₅- represents the substituted benzene ring and the

CHO should represent the functional group of aldehyde

8 0

3 years ago

Read 2 more answers

A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume

pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of $N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol$

amount of $SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol$

mole fraction of $N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330$

mole of fraction $SF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669$

PV = nRT

P of N_2 O $= \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa$

mole of SF_4 $=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa$

Total pressure = 39127.053 + 79126.36 = 118253.413 Pa

6 0

3 years ago

A ______ must be replaced after too much current in it causes it to melt.

Nezavi [6.7K]

A circuit breaker must be replaced after too much current flowing through it causing it to melt.

6 0

3 years ago