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xz_007 [3.2K]
3 years ago
5

What will the resistance be for a lamp that draws 4.6 amps of current from a 120-volt outlet? A. 550 ohms B. 115 ohms C. 26 ohms

D. 0.038 ohms E. 5.7 ohms
Physics
2 answers:
Neporo4naja [7]3 years ago
5 0
To answer the question above, use the equation,
                                    V = I x R
where V is the potential difference or voltage, I is current, and R is the resistance. Substituting the known values,
                                  120 V = (4.6 amps) x R
The value of R is 26.09 ohms. Therefore, the answer is letter C. 
Paraphin [41]3 years ago
3 0
R = V/I = 120 / 4.6 ≈ 26 ohms.

Option C.
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ehidna [41]

Answer:

A.  when the mass has a displacement of zero

Explanation:

The velocity of a mass on a spring can be calculated by using the law of conservation of energy. In fact, the total energy of the mass-spring system is equal to the sum of the elastic potential energy (U) of the spring and the kinetic energy (K) of the mass:

E=U+K=\frac{1}{2}kx^2 + \frac{1}{2}mv^2

where

k is the spring constant

x is the displacement of the mass with respect to the equilibrium position of the spring

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v is the velocity of the mass

Since the total energy E must remain constant, we can notice the following:

- When the displacement is zero (x=0), the velocity must be maximum, because U=0 so K is maximum

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Based on these observations, we can conclude that the velocity of the mass is at its maximum value when the displacement is zero, so the correct option is A.


8 0
3 years ago
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A girl pulls on a 10-kg wagon with a constant horizontal force of 30 n. if there are no other horizontal forces, what is the wag
olga2289 [7]
Force = mass * acceleration
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Given m = 10 kg, F = 30 N;

F = ma
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The atmospheric pressure on the top of the Engineering Sciences Building (ESB) is 97.6 kPa, while that in Room G39-ESB (ground f
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Answer:

Δ h = 52.78 m

Explanation:

given,

Atmospheric pressure at the top of building = 97.6 kPa

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acceleration due to gravity, g = 9.8 m/s²

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We know,

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11.368 Δ h = 600

Δ h = 52.78 m

Hence, the height of the building is equal to 52.78 m.

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