1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex Ar [27]
3 years ago
7

URGENT__ mass is the measurement of fat on the body. Fat or lean

Physics
1 answer:
Nadya [2.5K]3 years ago
5 0

\huge\fbox\red{Lean}\

  • Lean body mass represents the weight of your muscles, bones, ligaments, tendons, and internal organs.

\small\mid{ \underline{ \overline{ \tt \: -ɪƭ'ꜱ \: ʙᴙᴜᴛᴀʟ \: σʋʇ \: ɦэŗǝ}} \mid}

You might be interested in
When white light passes through a prism, a red light is least changed in direction? True or false
Goryan [66]

True because the picture below proves this....

* from which red color is least deviated and violet most.

* Hopefully this helps:) Mark me the brainliest:) !!

<em>∞ 234483279c20∞</em>

4 0
3 years ago
A car stops in 130 m. If it has an acceleration of -5 m/s2 what was the cars starting velocity?
Tatiana [17]

Answer:

<u>We are given:</u>

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

<u>Solving for initial velocity:</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

8 0
3 years ago
Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(
lions [1.4K]

For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.

According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.

Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.

Learn more: brainly.com/question/17638582

8 0
2 years ago
Show that rigid body rotation near the Galactic center is consistent with a spherically symmetric mass distribution of constant
irakobra [83]

To solve this problem we will use the concepts related to gravitational acceleration and centripetal acceleration. The equality between these two forces that maintains the balance will allow to determine how the rigid body is consistent with a spherically symmetric mass distribution of constant density. Let's start with the gravitational acceleration of the Star, which is

a_g = \frac{GM}{R^2}

Here

M = \text{Mass inside the Orbit of the star}

R = \text{Orbital radius}

G = \text{Universal Gravitational Constant}

Mass inside the orbit in terms of Volume and Density is

M =V \rho

Where,

V = Volume

\rho =Density

Now considering the volume of the star as a Sphere we have

V = \frac{4}{3} \pi R^3

Replacing at the previous equation we have,

M = (\frac{4}{3}\pi R^3)\rho

Now replacing the mass at the gravitational acceleration formula we have that

a_g = \frac{G}{R^2}(\frac{4}{3}\pi R^3)\rho

a_g = \frac{4}{3} G\pi R\rho

For a rotating star, the centripetal acceleration is caused by this gravitational acceleration.  So centripetal acceleration of the star is

a_c = \frac{4}{3} G\pi R\rho

At the same time the general expression for the centripetal acceleration is

a_c = \frac{\Theta^2}{R}

Where \Theta is the orbital velocity

Using this expression in the left hand side of the equation we have that

\frac{\Theta^2}{R} = \frac{4}{3}G\pi \rho R^2

\Theta = (\frac{4}{3}G\pi \rho R^2)^{1/2}

\Theta = (\frac{4}{3}G\pi \rho)^{1/2}R

Considering the constant values we have that

\Theta = \text{Constant} \times R

\Theta \propto R

As the orbital velocity is proportional to the orbital radius, it shows the rigid body rotation of stars near the galactic center.

So the rigid-body rotation near the galactic center is consistent with a spherically symmetric mass distribution of constant density

6 0
3 years ago
D=1/2at^2 <br> solve for a
nignag [31]

Answer:

a = 2d / t²

Explanation:

d = ½ at²

Multiply both sides by 2:

2d = at²

Divide both sides by t²:

a = 2d / t²

4 0
3 years ago
Other questions:
  • What influences the strength of an electric field?
    8·1 answer
  • A grindstone of radius 4.0 m is initially spinning with an angular speed of 8.0 rad/s. The angular speed is then increased to 12
    6·1 answer
  • A foul ball is hit straight up into the air with a speed of about 25 m/s. ? how high does it go? (b) how long is it in the air?
    5·1 answer
  • Which explains how fossils for used as evidence about the theory of continental drift
    10·2 answers
  • Rubbing your hands together warms them by converting work into thermal energy. If a woman rubs her hands back and forth for a to
    15·1 answer
  • Which vector has a y-component with a length of 4?
    15·1 answer
  • __________________ have almost no mass. A.protons B.neutrons C.electrons D.atoms
    7·1 answer
  • Jonas and his family are moving to another part of the city. As Jonas, his brother, and his Dad were driving one of the trucks f
    12·2 answers
  • Why do bones weaken as a person gets older
    5·1 answer
  • What would happen to a ray of light when it enters: - a) glass to water b) water to air?​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!