3 years ago

Using the right amount of significant figures, calculate the answer to the following problem, 215.5+101.02555

Physics

1 answer:

cestrela7 [59]3 years ago

7 0

Answer:

This is how I figured it out:

215.5 rounded to one significant figure is 200
101.02555 rounded to one significant figure is 100.
200 + 100 = 300.

Hope this helps!

Explanation:

You might be interested in

a particle of mass m sits at rest at x = 0. At time t = 0 a force given by F = Fe^(-t/T) is applied in the +x direction; F and T

wlad13 [49]

Explanation:

Given: $F=m\ddot{x}=Fe^{-\frac{t}{T}}$

Solving for $\ddot{x}$ :

$\ddot{x}=\frac{F}{m}e^{-\sqrt{\frac{F}{m} } t}$

where:

$T=\sqrt{\frac{m}{F}}$

Integrating to get $\dot{x}$ with initial conditions $\dot{x}(0)=0$ :

$\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}} t}$

Integrating to get x with initial conditions x(0) = 0:

$x=-1+\sqrt{\frac{F}{m}} t+e^{-\sqrt{\frac{F}{m}}t}$

When t=T:

$x=-1+\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}+e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\frac{1}{e}$

$\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\sqrt{\frac{F}{m}}(1-\frac{1}{e})$

4 0

3 years ago

Pls help will give brainlest

Karo-lina-s [1.5K]

Respon

lqiudos ciopatmibes

ly apsamtios ccoriendor sabe r

llpop

io.

7 0

3 years ago

Read 2 more answers

Explain why a doctor might not give you any medication if you have a viral disease?

fomenos

Answer:

You never know if the medication could make you worse

Explanation:

5 0

3 years ago

Read 2 more answers

A machine has an efficiency of 70%. How much work dose the machine do when 20,000 J of work is done on it ?

Murrr4er [49]

Answer: The machine does 14.000 J

3 0

3 years ago

If 12V battery maintains a 4.5A current through a resistor what is the resistance of the resistor?

Dimas [21]

Answer:

2.7ohms

Explanation:

Given parameters:

Voltage of the battery = 12V

Current = 4.5A

Unknown:

Resistance of the resistor = ?

Solution:

From Ohm's law, we know that;

V = IR

V is the voltage

I is the current

R is the resistance

So;

R = $\frac{V}{I}$ = $\frac{12}{4.5}$ = 2.7ohms

5 0

3 years ago