The specific heat of mercury is 149.4 J/(kgK)
Explanation:
When a substance is supplied with an amount of energy Q, its temperature increases according to the equation:
where
is the increase in temperature
m is the mass of the sample
is its specific heat capacity
For the sample of mercury in this problem we have
Q = 275 J
m = 0.450 kg
Therefore, by re-arranging the equation we find the mercury's specific heat:
Learn more about specific heat capacity:
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Answer: The formula of Newtons second law of motion is F=MA so therefore it would be written like this Force = Mass X Acceleration
F = 5 x 2
F = 10 N
Answer:
Abby is standing (4.5^2 + 2.3^2)^1/2 from the far speaker
D2 = 5.05 m from the far speaker
The difference in distances from the speakers is
5.05 - 4.5 = .55 m (Let y be wavelength, lambda)
n y = 4.5
(n + 1) y = 5.05 for the speakers to be in phase at smallest wavelength
y = .55 m subtracting equations
f = v / y = 340 / .55 = 618 / sec should be the smallest frequency
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