6.) What is
1 answer:
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Answer:
The radius of the circle made by the person on the merry go round is 74.55 meters
Explanation:
The given parameters are;
The force the merry go round exerts on the rider = 1000 N
The time it takes the merry go round to make one complete revolution = 15 seconds
The weight of the person = 750 N
The radius of the circle made by the person on the merry go round = r
We have;
Where;
m = The mass of the person
v = The velocity of the person
= The centrifugal force acting on the person = 1,000 N
r = The radius of the circle made by the person on the merry go round
ω = Angular velocity = 2·π/15 rad/s
We have;
The mass of the person = The weight/(The acceleration due to gravity, g)
∴ The mass of the person = 750/9.81 ≈ 76.45 kg
By substituting the calculated and known values into the equation for the centripetal force, we have;
= m × ω² × r
1000 = 76.45 × (2·π/15)² × r
r = 1000/(76.45 × (2·π/15)²) = 74.55 m
The radius of the circle made by the person on the merry go round = r = 74.55 m.
The radius of the loop is 18.9 km
Explanation:
When the airplane is at the top of the loop, the pilot experiences two forces:
- The force of gravity, acting downward, of magnitude
- The normal reaction exerted by the seat on the pilot, also acting downward, N
Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:
where
m is the mass of the pilot
is the acceleration of gravity
N is the normal reaction
v = 430 m/s is the speed of the plane
r is the radius of the loop
Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,
N = 0
Therefore the equation becomes
And so we can find the radius of the loop:
Learn more about circular motion:
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