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Nikolay [14]
3 years ago
11

A board is 7 3/4 feet in length. How many full size pieces of board 1 1/3 feet in length can a carpenter cut from that board of

wood?
Mathematics
2 answers:
Kobotan [32]3 years ago
7 0

Evaluate.

7 3/4 ÷ 1 1/3 = 31/4 ÷ 4/3 = 31/4 × 3/4 = 93/16 = 5 13/16 (round down)

answer: 5 full boards

Savatey [412]3 years ago
6 0
The carpenter can cut six full sized pieces of board.
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Ne4ueva [31]

In 15 diffret days 15/4 inches of rain fell in April month if every day rained 1/4 of a inch .

How to find the rain fell in 15 diffret days ?

We know that rain in every day is 1/4 of a inch

So for 15 days

1/4+1/4+1/4+......15times\\=15/4

So in 15 diffret days in April rain fell is 15/4 inches.

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8 0
2 years ago
Some people know this can yall help
vlada-n [284]

Answer:

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Step-by-step explanation:

36 ÷ ( x + 9 ) = ???

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5 0
2 years ago
What is a multiple of 7 and is also a factor of 7
olga2289 [7]
28 is a multiple of 7 and also a factor of seven!
4 0
3 years ago
The Width of a rectangle is 2w+3. The length is equal to 4 times its width. Write an expression to represent the perimeter of th
kupik [55]
Since the perimeter is the sum of the length of all sides we multiply width and length by 2 and then add them together

4 0
3 years ago
PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
3 years ago
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