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vfiekz [6]
3 years ago
12

Calcium chloride is used to make pickles. The calcium atom transfers electrons to chlorine atoms, leading to the formation of ch

emical bonds. Calcium chloride contains bonds.
A. Covalent
B. Ionic
C. Metallic
Copper atoms are used to produce pennies. The copper atoms in pennies share many electrons. Pennies contain bonds.
A. Covalent
B. Ionic
C. Metallic
Hydrochloric acid is the main acid that helps break down food in the stomach. The atoms of hydrochloric acid share electrons. Hydrochloric acid contains bonds.
A. Covalent
B. Ionic
C. Metallic
Physics
2 answers:
Sveta_85 [38]3 years ago
6 0

Answer: Calcium chloride contains ionic bond.

Copper pennies contain metallic bond.

Hydrochloric acid contains covalent bonds.

Explanation:

Covalent bond is a type of chemical bond in which equal sharing of the electrons takes place between both the atoms.When two atoms with slight or zero difference in their electronegatives  gets combined they form covalent bond.

Calcium chloride contain ionic bond.

Ionic bond is a type of chemical bond in which completer transfer of electrons take place between both the atoms. When two atoms with large difference in their electronegatives gets combined they form ionic bond.

Hydrochloric acid has covalent bond.

Metallic bond is type of chemical bonding which holds together the metal atoms. The electrostatic force between the conduction electrons and the positively charged metal ions. In this bonding ,sharing of electrons is extended over the entire molecular structure.

Copper pennies contain metallic bond.

GarryVolchara [31]3 years ago
3 0

Calcium chloride contains ionic bonds.

Pennies contain metallic bonds.

Hydrochloric acid contains covalent bonds.



You're welcome.

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Use the dimensional analysis and check the correctness of given equation:-<br> PV= nRT
Harman [31]

PV=nRT

Here

P=Pressure

V=Volume

n=Molarity

R=universal gas constant

T=Temperature.

LHS

\\ \tt\bull\leadsto PV

\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]

\\ \tt\bull\leadsto [ML^5T^{-2}]

RHS

\\ \tt\bull\leadsto nRT

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3 years ago
An object moves along the x axis. The graph shows it’s position x as a function of time t. Find the average velocity of the obje
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Question is from B to C

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A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu
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Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

(a)60 (b)90 (c)120

Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

F=I \times B \times L \times sin(\theta)

So from data

F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N

Now sub parts

(a)

\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N

(b)

\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N

(c)

\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N

3 0
3 years ago
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