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garri49 [273]
3 years ago
12

What would it feel like to walk on the surface of the moon??

Chemistry
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0
Well it's a new experience but it can be hard to even start walking at first and hard to stop because of the slippery dust underfoot and less traction to the ground in lower gravity.
Cloud [144]3 years ago
6 0
I'm pretty sure it would feel like magic, You could definitely float when you jump  
You might be interested in
1. The s orbitals are not symmetrical in shape.<br> a. TRUE<br> O. FALSE
ira [324]

The s orbitals are not symmetrical in shape is a FALSE statement.

An s orbital is so symmetric, more specifically spherically symmetric that it looks the same from all directions.

  • The atomic orbitals in the atoms of elements differ in shape.

In essence, the electrons they describe have varying probability distributions around the nucleus. The spherical symmetry of s orbitals is evident in the fact that all orbitals of a given shell in the hydrogen atom have the same energy.

  • All s orbitals are spherically symmetrical. Put simply, an electron that occupies an s orbital can be found with the same probability at any orientation (at a distance) from the nucleus.

The s orbitals are therefore represented by a spherical boundary surface which is a surface which captures a high proportion of the electron density.

Read more:

brainly.com/question/5087295

4 0
2 years ago
Newton's Law of Gravity says that any the effect of gravity between two objects depends on what two factors?
maw [93]
The masses of the objects and the distance between them
-hope it helps
8 0
3 years ago
What major events cause islands to form in the pacific ocean
zmey [24]
One of the major events is Volcanos etc...
4 0
3 years ago
Read 2 more answers
The combustion of ethyne, shown below unbalance, produces heat which can be used to weld metals:
Andreyy89

Answer:

3.69 g

Explanation:

Given that:

The mass m = 325 g

The change in temperature ΔT = ( 1540 - 165)° C

= 1375 ° C

Heat capacity c_p = 0.490 J/g°C

The amount of heat required:

q = mcΔT

q =  325 × 0.490 × 1375

q = 218968.75 J

q = 218.97 kJ

The equation for the reaction is expressed as:

C_2H_{2(g)} + 5O_{2(g)} \to 2CO_{2(g)} + H_2O_{(g)}   \ \   \ \ \  \Delta H^o_{reaction} = -1544 \ kJ

Then,

1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.

Thus, for 218.97 kJ, the amount of ethyne gas required will be:

= \dfrac{26 \ g}{1544 \ kJ} \times 218.97 \ kJ

= 3.69 g

3 0
3 years ago
An important reaction in the formation of photochemical smog is the photodissociation of NO2: NO2 + hv &gt;&gt;&gt; NO(g) + O(g)
vaieri [72.5K]

Explanation:

NO_2 + hv\rightarrow NO(g) + O(g)

The maximum wavelength of light that can cause this reaction is 420 nm.

a) The wavelength given lies in the range of visible light range that is from 400 nano meters to 700 nano meters.

The light with wavelength of 420 nm is found in the range of visible light.

b)The maximum strength of a bond :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = Energy required to break single molecule of nitrogen dioxide

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 420 nm=420\times 10^{-9}m

E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8 m/s}{420\times 10^{-9}m}

E=4.733\times 10^{-19} J

Energy required to break 1 mole of nitrogen dioxide molecules:

= E\times N_A=4.733\times 10^{-19} J\times 6.022\times 10^{23} mol^{-1}

=285,012.66 J/mol=285.13 kJ/mol

(1 J = 0.001 kJ )

285.13 is the maximum strength of a bond, in kJ/mol, that can be broken by absorption of a photon of 420-nm light.

c) the photodissociation reaction showing Lewis-dot structures is given in an image attached.

6 0
4 years ago
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