Answer:
The van't hoff factor of 0.500m K₂SO₄ will be highest.
Explanation:
Van't Hoff factor was introduced for better understanding of colligative property of a solution.
By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.
a) For NaCl the van't Hoff factor is 2
b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]
Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.
c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.
The percentage yield of the new production technique is 82.8%
<h3>What is the percentage yield?</h3>
Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.
We are told in the question that there are three shifts;
Shift 1 produces 4562 grams
Shift 2 produces 5783 grams
Shift 3 produces 5247 grams
Average production from the three shifts = 4562 grams + 5783 grams + 5247 grams/3 = 5197 grams
The theoretical average yield is = 7000 grams + 7000 grams + 7000 grams/3 = 7000 grams
Now the percentage yield = actual yield/ theoretical yield * 100/1
percentage yield = 5197 grams/7000 grams * 100/1
percentage yield = 82.8%
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Answer:
6.460 gm is the correct answer .
Explanation:
Given
Kate’s blood volume=
blood glucose=
As we know that

The
includes the blood glucose of the 
So
of the Kate’s blood volume can be determined by



To convert into the gm we have divided by the 1000

Therefore the glucose in her blood=

Since the bell weighs 190 N and is 45 m high, the bell’s potential energy is 8550 J
To answer the question, we need to know what potential energy is.
<h3>What is potential energy?</h3>
This is energy due to position. It is given by PE = mgh where
- m = mass,
- g = acceleration due to gravity and
- h = height of object.
Also, W = mg = weight of object.
So, PE = Wh
<h3>
The bell's potential energy</h3>
Now, given that the bells weight 190 N and is 45 m high,
So, PE = Wh
= 190 N × 45 m
= 8550 Nm
= 8550 J
So, the bell’s potential energy is 8550 J
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