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3 years ago

What are the 5 common uses of fossil fuels?

Chemistry

1 answer:

Leni [432]3 years ago

5 0

Answer:

Electricity. Coal alone provides half the electricity in the United States. ...

Heating. Oil and natural gas are commonly used for heating homes as well as providing heat for industrial applications.

Transportation. Oil supplies 99 percent of the energy for cars in the form of gasoline and diesel. ...

Limits. ...

Considerations.

Explanation:

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How many grams of glucose are needed to prepare 144.3 mL of a 1.4%(m/v) glucose solution?

Montano1993 [528]

Answer:

2.0202 grams

Explanation:

1.4% (m/v) glucose solution means: 1.4g glucose/100mL solution.

so ?g glucose = 144.3 mL soln

Now apply the conversion factor, and you have:

?g glucose = 144.3mL soln x (1.4g glucose/100mL soln).

so you have (144.3x1.4/100) g glucose= 2.0202 grams

6 0

3 years ago

Read 2 more answers

DUE TOMORROW!!! 15 POINTS

Lunna [17]

Answer:

A. write balanced chemical equation (including states), for this process.

Explanation:

Almost all hydrocarbon 'burn' reactions involve oxygen; it's by far the most reactive substance in air.

Hydrocarbon combustions always involve

[some hydrocarbon] + oxygen --> carbon dioxide + steam.

C6H6(l) + O2 (g)--> CO2 (g)+ H2O (g)

Balance carbon, six on each side:

C6H6(l) + O2 (g)--> 6CO2 (g)+ H2O (g)

Balance hydrogen, six on each side:

C6H6(l) + O2 (g)--> 6CO2(g) + 3H2O (g)

Now, we have fifteen oxygens on the right and O2 on the left.

Two ways to deal with that. We can use a fraction:

C6H6 (l)+ (15/2)O2 (g)--> 6CO2 (g)+ 3H2O (g)

Or, if you prefer to have whole number coefficients, double everything

to get rid of the fraction:

2C6H6 (l)+ 15O2 (g)--> 12CO2 (g)+ 6H2O (g)

With the SATP states thrown in...

C6H6(l) + (15/2)O2(g) --> 6CO2(g) + 3H2O(g)

6 0

3 years ago

Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur

Alenkinab [10]

Answer:

$\large \boxed{\text{-10.0 kJ}}$

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

$w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}$

The negative sign indicates that the work was done against the surroundings.

4 0

3 years ago

Fireworks, KNO3<br> Give only the names of the elements alphabetically, separating them with commas.

Alborosie

Answer : The question is to write the elements alphabetically and seperating them with commas.

So in this case for your question of Fireworks , K $NO_{3}$ ,

The answer will be K, N, O.

You have to just differentiate the elements and write them according to the alphabetical order.

4 0

3 years ago

Read 2 more answers

Which of the following atoms will not react with water? A. K B. Li C. Pb D. Na

Montano1993 [528]

The answer would be C. Pb

3 0

3 years ago