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Darina [25.2K]
3 years ago
11

Demonstrate a net force of 50 N to the left. Use three different combinations of people to get the same net force. How many peop

le did you place on each side?
Chemistry
2 answers:
balandron [24]3 years ago
7 0
They Combined together
Evgesh-ka [11]3 years ago
6 0

Answer:

They started to combine the forces all together.

You might be interested in
Change the following word equation into balanced formula equation
Natali [406]

Answer:

Fe + CuO ----> FeO+ Cu

Explanation:

A word equation is a chemical equation in which the reactants and products are represented by words rather than the respective symbols of the species involved in the reaction.

Generally, when writing a balanced reaction equation, it is normal to ensure that the number of atoms of each element on the reactant side is the same as the number of atoms of the same element on the product side. This has been ensured in the reaction above.

The reaction above is possible because iron is higher than copper in the electrochemical series hence iron can displace copper from its compounds.

6 0
2 years ago
Perform the following calculation and report the answer with the correct number of significant figures.
Paul [167]

Answer:

81.72 +0.73=82.45

Explanation:

  • you need to add it

1

81.72

+0.73

= 82.45

8 0
2 years ago
Read 2 more answers
For a particular reaction, ΔH=−111.4 kJ/mol and ΔS=−25.0 J/(mol·K).
PtichkaEL [24]
That’s the answer ^^^^
3 0
3 years ago
What is the mass of 1.2 x 1023 atoms of arsenic?
Gre4nikov [31]

Answer:

14.93 g

Explanation:

First we <u>convert 1.2 x 10²³ atoms of arsenic (As) into moles</u>, using <em>Avogadro's number</em>:

  • 1.2 x 10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.199 mol As

Then we can<u> calculate the mass of 0.199 moles of arsenic</u>, using its<em> molar mass</em>:

  • 0.199 mol * 74.92 g/mol = 14.93 g

Thus, 1.2x10²³ atoms of arsenic weigh 14.93 grams.

6 0
3 years ago
A 2.5 g sample of french fries is placed in a calorimeter with 500.0 g of water at an initial temperature of 21 °C. After combus
SIZIF [17.4K]
Q=m°C<span>ΔT
=(500g) x (1 cal/g.</span>°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal

<span>"What is the caloric value (kcal/g) of the french fries?"
13.5 kcal/ 2.5 g = 5.4 kcal/g</span>
8 0
3 years ago
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