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LekaFEV [45]
3 years ago
6

explain why elements lying on the extreme right of the periodic table as from non metals but those lying on the extreme left a s

trong metals
Chemistry
1 answer:
kvasek [131]3 years ago
5 0
Element at Extreme Left In Periodic Table:
                                                                   The elements of Group I-A (1) are present at extreme left of the periodic table. They are called as Alkali Metals. Alkali Metals are strong metals. These elements can easily loose their valence electron. The valence shell electronic configuration of these elements is,

                                                     ns¹

where n is principle quantum number, which shows main energy level or shell. These metals can gain Noble gas configuration (stable configuration) either by loosing one electron or by gaining seven or more electrons. As it is quite reasonable to loose one electron instead of gaining seven or more electrons so these element easily loose one electron to gain noble as configuration. The Metallic character decreases along the period from left to right. So Group II-A (2) are second most metallic elements and so on. These metals at extreme left mainly exist in solid form.

Element at Extreme Right In Periodic Table:
                                                                     Elements present at extreme right of the periodic table lacks the properties of metallic character and act as non-Metals. They have almost complete outermost shell or have the deficiency of one or two electrons. They are not as hard as metallic elements and they exist with complete octet like in Noble gases, or deficient with one electron (Halogens) or two electrons (oxygen group). These elements tend to gain or accept electron if their valence shell is deficient with required number of elements. Like the valence electronic configuration of Halogens is,

                                                   ns², np⁵

So, Halogens readily accept one electron and attain noble gas configuration. Elements at extreme left exist mainly in gas phase.
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Answer:

Explanation:

The reaction is given as:

N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}

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From the given information:

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[NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}

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[N_2] = 0.006857

[H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}

[H_2] = 9.17 \times 10^{-3}

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Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135

However; given that:

K_c = 1.2

By relating Q_c \ \ and  \ \ K_c, we will realize that Q_c \ \ <  \ \ K_c

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

7 0
2 years ago
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3 years ago
Which statement is true about a pseudoscientific idea? It is biased in its results. It can be tested and observed. It can be rep
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3 years ago
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Answer:

Combination reaction or synthesis reaction

Explanation:

Given reaction:

                 CO  +  H₂O  →  H₂CO₃

The type of reaction shown above is a combination or synthesis reaction. A combination reaction is one in which a single product is formed from two or more reactants.

In the given reaction carbon monoxide combines with water to produce hydrogen carbonate.

The formation of compounds from the union of their constituent elements falls into this category of reactions.

4 0
2 years ago
A student adds a rectangular block of mass 26.10 g to a graduated cylinder initially filled with 40.1 mL of water, but some wate
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The splash cause the volume of the block to be too high

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This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.

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