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xz_007 [3.2K]
3 years ago
14

How do particles in a solid move?

Chemistry
1 answer:
satela [25.4K]3 years ago
8 0

Answer:

The particles in a solid vibrate in place.

Explanation:

The particles in a solid are close and tightly packed together so they have no room to flow past each other like the particles in a liquid can.

Hope this helps!

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Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.
Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n}{W_s}

where,

n = moles of solute

W_s = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg

Now put all the given values in the formula of molality, we get

Molality=\frac{0.241}{0.0137kg}=17.6mole/kg

Therefore, the molality of solution is 17.6 mole/kg

3 0
3 years ago
Based on your graph in the Periodic Trends Lab, what is the relationship between atomic radius and ionization energy ?
maxonik [38]
As the atomic radius decreases, it becomes harder to remove an electron that is closer to a more positively charged nucleus. ... They experience a weaker attraction to the positive charge of the nucleus. Ionization energy increases from left to right in a period and decreases from top to bottom in a group.
6 0
3 years ago
The volume of the aquarium in our classroom is 1890 L. The density of seawater is 1.03g/cm^3. What is the mass of the water in o
guapka [62]
Density can be calculated using the following rule:
density = mass / volume
therefore,
mass = density x volume
From the givens:
we have the density = 1030 kg/m^3 and volume = 1.89 m^3

Substitute in the equation to get the mass as follows:
mass = 1030 x 1.89 = 1.9467 x 10^3 kg
5 0
2 years ago
Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict wheth
Elena-2011 [213]

Answer:

\Delta S_{surr} = + 0.32113\: kJ/K

Explanation:

Given: Entropy of surrounding: ΔSsurr = ?

Temperature: T= 355 K

The change in enthalpy of reaction: ΔH = -114 kJ

Pressure: P = constant

As we know, ΔH = -114 kJ ⇒ negative

Therefore, the given reaction is an exothermic reaction

Therefore, Entropy of surrounding at <em>constant pressure</em> is given by,

\Delta S_{surr} = \frac{-\Delta H}{T}

\therefore \Delta S_{surr} = -\left (\frac{-114 kJ}{355 K}  \right ) = + 0.32113\: kJ/K > 0

<u><em>In the given reaction:</em></u>

2NO(g) + O₂(g) → 2NO₂(g)

As, the number of moles of gaseous products is less than the number of moles of gaseous reactants.

\therefore \Delta S_{system} <  0

As we know, <em>for a spontaneous process, that the total entropy should be positive.</em>

\Delta S_{total} = \Delta S_{surr} + \Delta S_{system} > 0  

<u>Therefore, at the given temperature,</u>

  • if \Delta S_{surr} > \Delta S_{system} \Rightarrow \Delta S_{total} > 0 then the given reaction is spontaneous
  • if \Delta S_{surr} < \Delta S_{system} \Rightarrow \Delta S_{total} < 0 then the given reaction is non-spontaneous
6 0
3 years ago
Which of the following is an advantage angiosperms and gymnosperms have over mosses?
Valentin [98]

Answer:

they are seed producing so can populate more areas

8 0
3 years ago
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