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fenix001 [56]
3 years ago
13

A concrete mix design calls for 6.5 sacks of cement, a water/cement ratio of 0.45, and an air content of 2.5%. 1. Complete the m

ix design usage chart below by filling in the shaded cells. Material Type Description Design Quantity Specific Gravity Volume (ft3 ) Cement Type II lb 3.15 Coarse Aggregate ¾" x #4 1,190 lb 2.75 Coarse Aggregate ⅜" x #8 lb 2.72 Fine Aggregate Concrete Sand 1,453 lb 2.66 Water Mixing Water gal 1.00 Air % by Volume 2.5% - Yield lb - 27.00 2. What is the unit weight of this mix in pcf?
Engineering
2 answers:
RUDIKE [14]3 years ago
7 0

Answer:

28.6 kg

Explanation:

The final weight can be calculated from the mixing data and formulae which is given as follows:

cement content = \frac{water content}{water - cement ratio}

Computing the parameters and checking the tables gives 28.6 kg.

4vir4ik [10]3 years ago
5 0

Answer:

The answer is 28.6 kg

Explanation:

The final weight can be calculated from the mixing data and formulae which is given as follows:

cement content = water content divided by (water minus cement ratio)

Therefore:

Cement content = water content/(water - cement ratio)

After all the parameters had been imputed and calculated, we will arrive at a value of 28.6 kg.

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Order of Design Process steps ?
gregori [183]

Answer:

The five stages of Design Thinking, according to d.school, are as follows: Empathise, Define , Ideate, Prototype, and Test. Let's take a closer look at the five different stages of Design Thinking

Explanation:

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2 years ago
Water exiting the condenser of a power plant at 45 Centers a cooling tower with a mas flow rate of 15,000 kg/s. A stream of cool
MariettaO [177]

Answer: hello your question is incomplete below is the missing part

question :Determine the temperature of the cooled water exiting the cooling tower

answer : T  = 43.477° C

Explanation:

Temp of water at exit = 45°C

mass flow rate of cooling tower = 15,000 kg/s

Temp of makeup water = 20°C

Assuming an atmospheric pressure of = 101.3 kPa

<u>Determine temperature of the cooled water exiting the cooling tower</u>

Water entering cooling tower at 45°C

Given that Latent heat of water at 45°C = 43.13 KJ/mol

Cp(wet air) = 1.005+ 1.884(y1)

where: y1 - Inlet mole ratio = (0.01257) / (1 - 0.01257) = 0.01273

Hence : Cp(wet air) = 29.145 +  (0.01273) (33.94) = 29.577 KJ/kmol°C

<u>First step : calculate the value of Q </u>

Q = m*Cp*(ΔT) + W(latent heat)

Q = 321.6968 (29.577) (40-30) +  43.13 (18.26089)

Q =  95935.8547 KJ/s

Given that mass rate of water = 15000 kg/s

<u>Hence the temperature of the cooled water can be calculated using the equation below</u>

Q = m*Cp*∆T

Cp(water) = 4.2 KJ/Kg°C

95935.8547 = (15000)*(4.2)*(45 - T)

( 45 - T ) = 95935.8547/ 63000.    ∴ T  = 43.477° C

5 0
2 years ago
2. (Problem 4.60 on main book, diameters different) Water flows steadily through a fire hose and nozzle. The hose is 35 mm diame
Viefleur [7K]

Answer:

coupling is in tension

Force = -244.81 N

Explanation:

Diameter of Hose ( D1 ) = 35 mm

Diameter of nozzle ( D2 ) = 25 mm

water gage pressure in hose = 510 kPa

stream leaving the nozzle is uniform

exit speed and pressure = 32 m/s and atmospheric

<u>Determine the force transmitted by the coupling between the nozzle and hose </u>

attached below is the remaining part of the  detailed solution

Inlet velocity ( V1 ) = V2 ( D2/D1 )^2  

= 32 ( 25 / 35 )^2

= 16.33 m/s

4 0
2 years ago
I need help with this I dont know the word ​
DiKsa [7]

Would it be Unit?

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5 0
3 years ago
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According to the video, what are examples of systems that Stationary Engineers oversee? Check all that apply. electrical systems
garik1379 [7]

Answer:

electrial systems

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Explanation:

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2 years ago
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