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fenix001 [56]
3 years ago
13

A concrete mix design calls for 6.5 sacks of cement, a water/cement ratio of 0.45, and an air content of 2.5%. 1. Complete the m

ix design usage chart below by filling in the shaded cells. Material Type Description Design Quantity Specific Gravity Volume (ft3 ) Cement Type II lb 3.15 Coarse Aggregate ¾" x #4 1,190 lb 2.75 Coarse Aggregate ⅜" x #8 lb 2.72 Fine Aggregate Concrete Sand 1,453 lb 2.66 Water Mixing Water gal 1.00 Air % by Volume 2.5% - Yield lb - 27.00 2. What is the unit weight of this mix in pcf?
Engineering
2 answers:
RUDIKE [14]3 years ago
7 0

Answer:

28.6 kg

Explanation:

The final weight can be calculated from the mixing data and formulae which is given as follows:

cement content = \frac{water content}{water - cement ratio}

Computing the parameters and checking the tables gives 28.6 kg.

4vir4ik [10]3 years ago
5 0

Answer:

The answer is 28.6 kg

Explanation:

The final weight can be calculated from the mixing data and formulae which is given as follows:

cement content = water content divided by (water minus cement ratio)

Therefore:

Cement content = water content/(water - cement ratio)

After all the parameters had been imputed and calculated, we will arrive at a value of 28.6 kg.

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A sum of $500,000 will be invested by a firm two years from now. If money is worth 12%, what will be the worth of this investmen
notka56 [123]

Answer:

investment 10 years from now is $1,238,000 .

Explanation:

given data

sum = $500,000

rate = 12% =0.12

total time = 10 year

solution

as present value After 2 years from now is $500,000

so time period is now = 8 year  ( 10 - 2 )

so we apply future value formula that is

Future value  = present value × (1+r)^{t}   ............1

put here value we get

Future value  = $500,000 × (1+0.12)^{8}  

Future value  = $500,000 × 2.476

Future value  = $1,238,000  

so investment 10 years from now is $1,238,000 .

8 0
3 years ago
All of these are true about GMA (MIG) welding EXCEPT that:
Hatshy [7]

Answer:

the welding gun liner regulates the shielding gas.

Explanation:

The purpose of the welding gun liner is to properly position the welding wire from the wire feeder till it gets to the nozzle or contact tip of the gun. <em>Regulation of the shielding gas depends on factors such as the speed, current, and type of gas being used. </em>In gas metal arc welding, an electric arc is used to generate heat which melts both the electrode and the workpiece or base metal.

The electric arc produced is shielded from contamination by the shielding gas. The heat generated by the short electric arc is low.

3 0
2 years ago
A hydraulic jump is induced in an 80 ft wide channel.The water depths on either side of the jump are 1 ft and 10 ft.Please calcu
krek1111 [17]

Answer:

a) 42.08 ft/sec

b) 3366.33 ft³/sec

c) 0.235

d) 18.225 ft

e) 3.80 ft

Explanation:

Given:

b = 80ft

y1 = 1 ft

y2 = 10ft

a) Let's take the formula:

\frac{y2}{y1} = \frac{1}{5} * \sqrt{1 + 8f^2 - 1}

10*2 = \sqrt{1 + 8f^2 - 1

1 + 8f² = (20+1)²

= 8f² = 440

f² = 55

f = 7.416

For velocity of the faster moving flow, we have :

\frac{V_1}{\sqrt{g*y_1}} = 7.416

V_1 = 7.416 *\sqrt{32.2*1}

V1 = 42.08 ft/sec

b) the flow rate will be calculated as

Q = VA

VA = V1 * b *y1

= 42.08 * 80 * 1

= 3366.66 ft³/sec

c) The Froude number of the sub-critical flow.

V2.A2 = 3366.66

Where A2 = 80ft * 10ft

Solving for V2, we have:

V_2 = \frac{3666.66}{80*10}

= 4.208 ft/sec

Froude number, F2 =

\frac{V_2}{g*y_2} = \frac{4.208}{32.2*10}

F2 = 0.235

d) El = \frac{(y_2 - y_1)^3}{4*y_1*y_2}

El = \frac{(10-1)^3}{4*1*10}

= \frac{9^3}{40}

= 18.225ft

e) for critical depth, we use :

y_c = [\frac{(\frac{3366.66}{80})^2}{32.2}]^1^/^3

= 3.80 ft

7 0
3 years ago
Read 2 more answers
You are asked to design a software package for an On-line Banking System (OBS). The OBS will take requests from its user on the
Anit [1.1K]

Answer:

From the statements described above,The proposed software package Online Banking System(OBS) shall provide the following services to the customer(account holder)

Receive all transaction requests from the customers trough online to perform banking activities

Offer a variety of services in banking like:

Opening an account with facilities of Savings,Checking and CD

Issuing checks and check clearance

Transfer of funds between savings and checking account

Establishing a CD(Certificate of Deposit)

Performing routine activities like

Deposit or withdraw funds from a checking account

Closing an account in one of the following operation

Complete closure of account

Closing only savings account

Withdraw CD (on Maturity of CD deposits) and close CD account

Unlike traditional Banking system, OBS offers all the operations through On-line mode over the internet thereby it eliminates manual intervention for the banking transactions from the Bank's side for most of the transactions except some cases like verification of new account applications or complaint redressal and technical support .In such cases ,There will be some users of the software with special privileges to access certain services to perform activities like user data verification and technical support.

Step:1 Identification of actors and software entities for the system to be implemented

The following are the actors identified in the system

Actors:

The users of the proposed system were classified as:

Customer : A user with an active account

Guest user:The user who applies for an account

Administrator:Maintainsand Controls OBS

Manager: Manages the transactions and Banking related issues

Technical Manager: Resolves technical issues of customers

Software entities:

Bank database :Maintains the data of all user accounts

Application server : Maintains the application software components and hosts the OBS website

Automatic Clearing House system : Processes transactions for checks

Step 2: Designing use cases

Use case diagrams are used to describe the system model by representing a set of use cases .Each use case represents a set of actions performed on the system by an actor.

The following are the two approaches of representing the system in a use case model:

1.Representing a use case for actions done by actors e.g. login , logout,message etc.,

2.Representing a use case for business process(Business use cases) e.g. transfer,registration etc.,

The following is the description of five possible business use cases for the requirements specified above

3 0
3 years ago
Question 7.1: Two possible overhead valve combustion chambers are being considered – the first has two valves; the second has fo
AleksandrR [38]

Answer:

1) The adoption of the second design we can see that the total valve perimeter is increased by 60.8%

2) Increase in flow are : 29%

3) Additional benefits in using 4 valves per cylinder:

a)For the purpose of controlling the combustion process, the inlet valves will give more flexibility

b) There is a larger valve throat areas for the flow of gas

Explanation:

1) Perimeter of the first possible overhead valve combustion chamber with two valves:

P₂ = πd = π × 23 = 72.26mm

Perimeter of the second possible overhead valve combustion chamber with four valves:

P₄ = π2d = π × 18.5 × 2 = 116.24 mm

If second design is adopted, percentage increase = ((P₄ - P₂)/P₂)×100

     = ((116.24 - 72.26)/72.26)×100 = 0.6086 ×100 = 60.86%

Therefore, the total valve perimeter is shown to have increased by 60.8%

2) Formula for flow Area (A) = P × L = πkd²

Area of the first possible overhead valve combustion chamber with two valves: A₂ = πkd² = πk(23)² = 1662k mm²

Area of the first possible overhead valve combustion chamber with four valves: A₄ = πkd² = 2πk(18.5)² = 2150k mm²

The percentage increase in flow area: ((A₄ - A₂)/A₄)×100 = ((2150 - 1662)/2150)×100 = 29%

3) The additional benefits of using are:

a) For the purpose of controlling the combustion process, the inlet valves will give more flexibility

b) There is a larger valve throat areas for the flow of gas

           

7 0
3 years ago
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