B) the plates are in constant motion and as a result the boundaries are where they interact
Answer:
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Explanation:
Answer:
stress = 8,556 Psi. or (stress = 59 Mpa)
Explanation:
stress = force / area
force P = 3 tons (convert to lbs. for units consistency)
1 ton = 2240 lbs.
P = 6,720 lbs.
steel bar Diameter D = 1 in. (convert to d
Area of steel bar = (π * 1²) / 4 = 0.785 in²
therefore, stress = 6720 lbs. / 0.785 in²
stress = 8,556 Psi.
in Mpa ----- 8556 Psi * 0.00689476 MPa/Psi = 59 Mpa
Answer:
(N-1) × (L/2R) = (N-1)/2
Explanation:
let L is length of packet
R is rate
N is number of packets
then
first packet arrived with 0 delay
Second packet arrived at = L/R
Third packet arrived at = 2L/R
Nth packet arrived at = (n-1)L/R
Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R
Now
L / R = (1000) / (10^6 ) s = 1 ms
L/2R = 0.5 ms
average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2
the average queuing delay of a packet = 0 ( put N=1)
Answer:
The answer is c-resistance