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3 years ago

(a) Design a first-order passive high-pass filter with a cutoff frequency of 1000 rad/sec.

Engineering

1 answer:

balu736 [363]3 years ago

6 0

Answer:

See the attachment

Verification shown in explanation

Explanation:

wc= 1/(RC)

The value of R and C shown in the attachment can be calculated as follows:

R=100 ohms

1000= 1/(100×C)

C= 10 microfarads

Gain= R/√(R²+Xc²)

at f=500, wc= 3142.59 rad/s

Xc= 1/(2πfC)

Xc=31.83

Gain= 100/√(100²+31.83²)

Gain= 0.953

at fc= 100, wc= 628.32 rad/s

Xc= 159.15

gain= 100/√(100²+ 159.15²)

gain= 0.532

As see form calculations that gain at low frequencies is smaller and gain at very high frequencies is near to 1. This means that at high frequencies Vin≈ Vout

Hence this filter allows high frequencies to pass but blocks low frequencies by lowering the gai

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To determine if a product or substance being used is hazardous, consult:__________.

qwelly [4]

Answer:

Option B: An MSDS

Explanation:

A dictionary is used to check up the meaning of general words and not for checking if a substance being used is hazardous. Option A is wrong.

MSDS means "Material Safety Data Sheet" and it contains documents with information that relates to occupational health & safety for checking various substances and products. Thus, option B is correct.

SAE stands for Society of Automotive Engineering and their standards pertain to mainly Automobiles. Thus option C is wrong.

EPA guidelines are mainly for checking facility and environmental health and safety compliance. Thus, option D is wrong.

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3 years ago

The amount of phase shift between input and output signal is important when measuring ____ circuit

svetoff [14.1K]

Answer:

The amount of phase shift between input and output signal is important when measuring a common emitter amplifier circuit.

Explanation:

the amount of phase shift between input and output signal is important when measuring a common emitter amplifier circuit

In signal processing, phase distortion is change in the shape of the waveform, that occurs when the phase shift introduced by a circuit is not directly proportional to frequency.

In a common emitter amplifier circuit there is an 180-degree phase shift between the input and output waveforms.

6 0

3 years ago

Thank you very much this helped a lot

Len [333]

Answer:

Your welcome i guess

Explanation:

7 0

3 years ago

Read 2 more answers

Rsidential Solar Solution:a. A type of photovoltaic solar panel manufactured in China receives a rating of 250W. The rating proc

aksik [14]

Answer:

a) $\eta = 13.455\%$ , b) $E_{day} = 812.716\,kJ$ , c) $C_{month. total} = 19.505\, USD$ , d) $t = 40.588\,years$

Explanation:

a) The area of the solar panel is:

$A = (20\,ft^{2})\cdot (\frac{0.3048\,m}{1\,ft} )^{2}$

$A = 1.858\,m^{2}$

The energy potential is determined herein:

$\dot E_{o} = (1000\,\frac{W}{m^{2}} )\cdot (1.858\,m^{2})$

$\dot E_{o} = 1858\,W$

The efficiency of the solar panel is:

$\eta = \frac{\dot E}{\dot E_{o}}\times 100\%$

$\eta = \frac{250\,W}{1858\,W}\times 100\%$

$\eta = 13.455\%$

b) The energy generated by the solar panel is presented below:

$E_{day} = (0.135)\cdot (150\,\frac{W}{m^{2}} )\cdot (20\,ft^{2})\cdot \left(\frac{0.3048\,m}{1\,ft} \right)^{2}\cdot (6\,h)\cdot (\frac{3600\,s}{1\,h} )\cdot (\frac{1\,kJ}{1000\,J} )$

$E_{day} = 812.716\,kJ$

c) The energy generated per month and per panel is:

$E_{month} = 30\cdot E_{day}$

$E_{month} = 30 \cdot (812.716\,kJ)\cdot \left(\frac{1\,kWh}{3600\,kJ} \right)$

$E_{month} = 6.773\,kWh$

Monthly energy savings due to the use of 18 panels are:

$C_{month, total} = 18\cdot E_{month}\cdot c$

$C_{month, total} = 18\cdot (6.773\,kWh)\cdot (\frac{0.16\,USD}{1\,kWh} )$

$C_{month. total} = 19.505\, USD$

d) The payback of the solar energy system is:

$t = \frac{9500\,USD}{12\cdot (19.505\,USD)}$

$t = 40.588\,years$

6 0

3 years ago

When the electrical connection to the alternator from the battery is not tight, it can cause?

Oksi-84 [34.3K]

Answer:

affects the flow of electricity

Explanation:

A loose battery terminal affects the flow of electricity. There is less power going to the electrical systems and the vehicle will not start or start sluggishly. Also, a loose battery terminal causes the car's electrical components like navigation, car lights, and audio among others to dim or fail completely.

3 0

2 years ago