The Bureau of Labor and Statistics predicted that the field of biomedical engineering would increase by 62 percent over the comi
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<h2>Answer:</h2>
24Ω
<h2>Explanation:</h2>
When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.
For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;
=
+
Solving for Rₓ gives;
=
------------------(i)
From the question;
Let
R₁ = resistance of first resistor = 40Ω
R₂ = resistance of second resistor = 60Ω
Now,
To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;
=
=
= 24 Ω
Therefore, the total resistance is 24Ω
Answer:
(a). The value of temperature at the end of heat addition process = 2042.56 K
(b). The value of pressure at the end of heat addition process = 1555.46 k pa
(c). The thermal efficiency of an Otto cycle = 0.4478
(d). The value of mean effective pressure of the cycle = 1506.41
Explanation:
Compression ratio = 8
Initial pressure = 95 k pa
Initial temperature = 278 °c = 551 K
Final pressure = 8 ×
= 8 × 95 = 760 k pa
Final temperature =
×
Final temperature = 551 ×
Final temperature = 998 K
Heat transferred at constant volume Q = 750
(a). We know that Heat transferred at constant volume =
⇒ 1 × 0.718 × ( - 998 ) = 750
⇒ = 2042.56 K
This is the value of temperature at the end of heat addition process.
Since heat addition is constant volume process. so for that process pressure is directly proportional to the temperature.
⇒ P ∝ T
⇒ =
⇒ =
× 760
⇒ = 1555.46 k pa
This is the value of pressure at the end of heat addition process.
(b). Heat rejected from the cycle
For the compression and expansion process,
⇒
⇒
⇒ = 1127.7 K
Heat rejected = 1 × 0.718 × ( 1127.7 - 551)
⇒ = 414.07
Net heat interaction from the cycle =
-
Put the values of &
we get,
⇒ = 750 - 414.07
⇒ = 335.93
We know that for a cyclic process net heat interaction is equal to net work transfer.
⇒ =
⇒ = 335.93
This is the net work output from the cycle.
(c). Thermal efficiency of an Otto cycle is given by
Put the values of &
in the above formula we get,
⇒ = 0.4478
This is the thermal efficiency of an Otto cycle.
(d). Mean effective pressure :-
We know that mean effective pressure of the Otto cycle is given by
=
---------- (1)
where is the swept volume.
=
---------- ( 2 )
From ideal gas equation
= m × R ×
Put all the values in above formula we get,
⇒ 95 × = 1 × 0.287 × 551
⇒ = 0.6
From the same ideal gas equation
= m × R ×
⇒ 760 × = 1 × 0.287 × 998
⇒ = 0.377
Thus swept volume = 0.6 - 0.377
⇒ = 0.223
Thus from equation 1 the mean effective pressure
⇒ =
⇒ = 1506.41
This is the value of mean effective pressure of the cycle.
Answer:
See attached pictures.
Explanation:
See attached pictures for detailed explanation.
