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JulijaS [17]
3 years ago
15

Why is it important we uncover and study fossils?

Physics
2 answers:
Ilia_Sergeevich [38]3 years ago
4 0

its important so we can learn things about the species  

timama [110]3 years ago
4 0

[ Answer ]

\boxed{We \ can \ use \ the \ past \ to \ learn \ about \ the \ future}

[ Explanation ]

When studying fossils, we can get a better image of how the Earth has changed through time. Fossils are no longer living. They are the remains of once living things, so by studying them, we can get an image of how they differ from animals and plants in our "today world."

We can learn about the future by studying the past. Certain weather patterns might have caused a species to adapt or go extinct, thus causing us to discover them and explore and create new ideas about the Earth and its secrets.

We can learn about life in the past from fossils. Fossils give us an accurate answer to all our guesses and hypothesis's. When studying these creatures or animals, we are able to sharpen our knowledge of the past.

\boxed{[ \ Eclipsed \ ]}

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The speed of water flowing through a hose increases from 2.05 m/s to 31.4 m/s as it goes through the nozzle. What is the pressur
Nimfa-mama [501]

The pressure in the hose as the speed of water changes from 2.05 m/s to 31.4 m/s as it goes through the nozzle is 5.92 × 10⁵ N/m².

Given:

The flow of water through the hose initially, v₁ = 2.05 m/s

The flow of water through the hose initially, v₂ = 31.4 m/s

Calculation:

From Bernoulli's equation we have:

P₁ + 1/2 ρv₁² + ρgh₁ = P₂ + 1/2 ρv₂² + ρgh₂

where P₁ is atmospheric pressure

           P₂ is the pressure in the hose

           ρ is the density of the fluid

           h₁ is the initial height

           h₂ is the final height

           v₁ is the initial velocity of the fluid

           v₂ is the final velocity of the fluid  and

           g is the acceleration due to gravity

Re-arranging the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (h₁-h₂)

Applying values in the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (0)

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [(31.4m/s)²-(2.05 m/s)²]

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [981.7575]

    = (1.01 × 10⁵ Pa)+ (4.91 × 10⁵ Pa)

    = 5.92 × 10⁵ Pa

    = 5.92 × 10⁵ N/m²

Therefore, the pressure in the hose is 5.92 × 10⁵ N/m².

Learn more about Bernoulli's equation here:

<u>brainly.com/question/9506577</u>

#SPJ4

6 0
1 year ago
A wheelbarrow is pushed with a force of 40 N. If 6,000 J of work is
stepladder [879]

Answer:

Distance = 150 meters

Explanation:

Given the following data;

Work done = 6,000 Joules

Force = 40 Newton

To find the total distance covered by the wheelbarrow;

Workdone = force * distance

Substituting into the formula, we have;

6000 = 40 * distance

Distance = 6000/40

Distance = 150 meters

Therefore, the total distance the wheelbarrow was pushed is 150 meters.

5 0
3 years ago
Electro-magnets are created by...
mojhsa [17]
Wrapping in insulated wire around a medal with ferromagnetic properties and applying an electric current
6 0
3 years ago
Which physical property is used to test the purity of metal ?
dimulka [17.4K]

The physical and chemical properties of metal can differ between the elements but if we try and generalize.


Physical properties are that they are hard, dense, shiny, malleable (can be bent), ductile (can be pulled into wires), a good conductor of heat and have high melting points meaning that they are solid at room temperature


Their chemical properties include being good electrical conductors, they make metallic bonds (ionic bonds with non-metals) and their atoms are arranged in a lattice. They release hydrogen when reacted with acids and are usually cations (positive ions).


4 0
3 years ago
An internal combustion engine does 356 kJ of useful work using 946 kJ of thermal energy from the gasoline consumed in the engine
OlgaM077 [116]

Answer:

The efficiency of this engine is 37.63 %.

Explanation:

Given;

useful output work done by the combustion engine, = 356 kJ

input work, = 946 kJ

The efficiency of the combustion engine is calculated as;

Efficiency = \frac{0utput \ work}{1nput \ work} \times 100\%\\\\Efficiency = \frac{356 \ \times \ 10^3}{946 \ \times \ 10^3} \times 100\%\\\\Efficiency = 37.63 \ \%

Therefore, the efficiency of this engine is 37.63 %.

3 0
2 years ago
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