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ankoles [38]
3 years ago
15

a sphere of diameter 6•0cm is moulded into a thin uniform wire of diameter 0•2mm.calculate the length of the wire in metres​

Physics
1 answer:
Scilla [17]3 years ago
7 0

The length of the wire is 36 m.

<u>Explanation:</u>

Given, Diameter of sphere = 6 cm

We know that, radius can be found by taking the half in the diameter value. So,

       \text { sphere radius, } R=\frac{D}{2}=\frac{6}{2}=3 \mathrm{cm}=3 \times 10^{-2} \mathrm{m}

Similarly,

      \text { wire radius, } r=\frac{0.2}{2}=0.1 \mathrm{mm}=1 \times 10^{-3} \mathrm{m}

We know the below formulas,

          \text {volume of sphere}=\frac{4}{3} \times \pi \times R^{3}

          \text {volume of wire}=\pi \times r^{2} \times l

When equating both the equations, we can find length of wire as below, where \pi=\frac{22}{7}

          \frac{4}{3} \times \pi \times R^{3}=\pi \times r^{2} \times l

         \frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-2}\right)^{3}=\frac{22}{7} \times\left(1 \times 10^{-3}\right)^{2} \times l

The \pi value gets cancelled as common on both sides, we get

           \frac{4}{3} \times 27 \times 10^{-6}=10^{-6} \times l

The 10^{-6} value gets cancelled as common on both sides, we get

           l=4 \times 9=36 m

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3 years ago
Which is the destructive interference formula for diffraction grating problems? dsin = dcos = dcos = n dsin = n.
shusha [124]

The destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

<h3>What is the definition of destructive interference?</h3>

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

\rm d sin \theta = n \lambda

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by \rm \lambda.

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

To learn more about destructive interference refer to the link;

brainly.com/question/16098226

5 0
2 years ago
At this rate, how long would it take for two continents 2900 km kilometers apart to collide?
Sophie [7]
At what rate??????????
3 0
3 years ago
If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 41 N · m, what minimum f
Marina86 [1]

We have that the Force  is mathematically given as

F=170.833N

<h3></h3><h3>Force </h3>

Question Parameters:

  • The torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 41 N · m,
  • the end of a 24 cm-long  wrench to <em>loosen </em>the nut

Generally the equation for the Force   is mathematically given as

F=\frac{T}{d}

Therefore

F=41/0.24

F=170.833N

For more information on Force visit

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3 0
2 years ago
A cyclist reaches the bottom of a hill with a speed of 18 m/s. Neglecting air resistance and other friction, to what maximum hei
JulsSmile [24]

Answer:

c) 17 m

Explanation:

From the conservation of energy.

Change in kinetic energy= change in potential energy

Now,

\Delta KE=\Delta PE

Now according to the situation.

\frac{1}{2}mv^{2}=mgh\\h=\frac{v^{2} }{2g}

Here, v is the velocity, m is the mass of an object, h is the height, g is the acceleration due to gravity.

Given that the speed of the bicycle is

v=18m/s

And the acceleration due to gravity is

g=9.8 m/s^{2}

Substitute these values.

h=\frac{18^{2} }{2\times 9.8}\\h=16.53m

Which means it is equivalent to 17 m

Therefore, the maximum height is 17 m

4 0
3 years ago
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