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olga55 [171]
3 years ago
13

Why the weight of a body decreases with increases in distance from the earth's surface​

Physics
2 answers:
Tom [10]3 years ago
6 0

because as the distance increases the gravitational force decreases so the weight of a body decreases

Bess [88]3 years ago
5 0

Answer:

Weight of the body decreases with increase in distance from the Earth because weight is inversely proportional to distance from the Earth which means Weight of the body decreases with increase in distance from the Earth and vice versa. Also Weight is "gravitational force exerted on the body" so as the distance from the Earth increases , the "gravitational force" decreases.

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Two cars approach each other. How does the
Lemur [1.5K]

Answer:

<u>The car's fast. The ground isn't moving.</u>

Hope this helped! :D

7 0
2 years ago
On the graph of voltage versus current, which line represents a 2.0 Ω resistor?​
Vikki [24]

Answer:

<h2>line B</h2>

Explanation:

According to ohm's law V = IR where;

V i sthe supply voltage (in volts)

I = supply current (in amperes)

R = resistance (in ohms)

In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.

For line B, R = ΔV/ΔI

R = V₂-V₁/I₂-I₁

R = 14.0-4.0/7.0-2.0

R = 10.0/5.0

R = 2.0ohms

Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.

3 0
4 years ago
11. What is the power output of a student who completes 86 J of work in 4 seconds?
Vika [28.1K]

Answer:

P=21.5Watts

Explanation:

Use P=w/t

So, P=86j/4s = 21.5w

8 0
3 years ago
Is there a difference between ragdoll and forward fold yoga pose​
saul85 [17]

Answer:

Yess their is a difference the ragdoll pose is a genteler variation of the forward fold yoga pose.

Explanation:

In ragdoll pose, you are meant to relax your entire upper body, allowing for a deep release of tension or stress that is stored in your body.

4 0
3 years ago
What is the mechanical energy of a 500kg rollercoaster car moving with a speed of 3m/s at the top hill that is 30m high
koban [17]

K.E = 1/2*m*v^2 = 1/2(500)(3)^2 = 2250 J

m*g*h = 500(9.8)(30) = 147000 J

2250 + 147000 = 149250

4 0
3 years ago
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