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alexdok [17]
3 years ago
13

Which of the following best describes the prime meridian?

Physics
1 answer:
ehidna [41]3 years ago
8 0
<h3><u>Answer;</u></h3>

A. The meridian at which longitude is defined to be 0 degrees

<h3><u>Explanation;</u></h3>
  • <em><u>Longitudes are imaginary lines going from south pole to north pole. These lines are known as meridians. Zero degrees longitude is an imaginary line known as the Prime Meridian or the Greenwich meridi</u></em>an.
  • The Prime meridian acts as the starting point for measuring distance both east and west around the Earth. The meridian runs through Greenwich, England and is internationally accepted as the line of 0 degrees longitude.
  • The lines of all longitudes or meridians are great circles, unlike in the case of lines of latitude where only the equator is a great circle.
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The force of gravity is twice as great on a 2-kg rock as on a 1-kg rock. Why then, dose the 2-kg rock not fall with twice the ac
Phoenix [80]

Answer:

because all objects fall at a rate of 9.8m/s²

8 0
3 years ago
An undamped 2.47 kg2.47 kg horizontal spring oscillator has a spring constant of 32.8 N/m.32.8 N/m. While oscillating, it is fou
olganol [36]

Answer:

0.631 m

6.53315 J

Explanation:

m = Mass = 2.47 kg

v = Velocity = 2.30 m/s

k = Spring constant = 32.8 N/m

A = Amplitude

In this system the energy is conserved

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{2.47\times 2.3^2}{32.8}}\\\Rightarrow A=0.631\ m

The amplitude is 0.631 m

Mechanical energy is given by

E=\dfrac{1}{2}mv^2\\\Rightarrow E=\dfrac{1}{2}2.47\times 2.3^2\\\Rightarrow E=6.53315\ J

The mechanical energy is 6.53315 J

5 0
3 years ago
A solid of density 8000 kgm.. weighs 0.8 kgf in air. When it is completely
ad-work [718]

Answer:<em> 0.5kg</em>

Explanation:

5 0
3 years ago
A curved, transparent object used to refract light
zlopas [31]
It's called a concave lens.
6 0
3 years ago
A one-dimensional plane wall of thickness 2l= 100 mm experiences uniform thermal energy generation of q˙= 800 w/m3 and is convec
slega [8]

Answer:

The thermal conductivity of the wall = 40W/m.C

h = 10 W/m^2.C

Explanation:

The heat conduction equation is given by:

d^2T/ dx^2 + egen/ K = 0

The thermal conductivity of the wall can be calculated using:

K = egen/ 2a = 800/2×10

K = 800/20 = 40W/m.C

Applying energy balance at the wall surface

"qL = "qconv

-K = (dT/dx)L = h (TL - Tinfinity)

The convention heat transfer coefficient will be:

h = -k × (-2aL)/ (TL - Tinfinty)

h = ( 2× 40 × 10 × 0.05) / (30-26)

h = 40/4 = 10W/m^2.C

From the given temperature distribution

t(x) = 10 (L^2-X^2) + 30 = 30°

T(L) = ( L^2- L^2) + 30 = 30°

dT/ dx = -2aL

d^2T/ dx^2 = - 2a

4 0
3 years ago
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