Question

A car moving at a speed of 8.0 meters per second enters a highway and accelerates at 3.0 meters per second^2. How fast will the car be moving after it has accelerated for 56 meters?

Answer 1

20 meters per second. I use the formula V^2=V0^2 + 2*a*d. a is acceleration and d is distance.

Answer 2

Answer:

Final speed of the car, v = 20 m/s

Explanation:

It is given that,

Initial speed of the car, u = 8 m/s

Acceleration of the car, $a=3\ m/s^2$

Let v is the speed of the car after it has accelerated for 56 meters. It can be calculated suing the third equation of motion. It is given by :

$v^2-u^2=2ad$

$v^2=u^2+2ad$  

$v^2=(8)^2+2\times 3\times 56$  

v = 20 m/s

So, the car is moving after it has accelerated for 56 meters is 20 m/s. Hence, this is the required solution.