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bija089 [108]
3 years ago
15

Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1. 2 m high. Student 2 pushes an identical box up a 5 m ra

mp from the floor to the top of the same table. Which student did the MOST work?.
Physics
1 answer:
valina [46]3 years ago
5 0

The student 2 did the MOST work because he pushed the box to a greater height.

The given parameters:

  • <em>Force applied by Student 1 = 500 N</em>
  • <em>Height of table for student 1 = 1.2 m</em>
  • <em>Height of ramp for student 2 = 5 m</em>

The work done by student 1 is calculated as follows;

Work = P.E = mgh

P.E = 1.2mg

The work done by the student 2 is calculated as;

P.E = 5mg

where;

  • <em>m </em><em>is the </em><em>mass </em><em>of the box</em>

Thus, we can conclude that the student 2 did the MOST work.

Learn more about work done here: brainly.com/question/8119756

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Explanation:

We have,

A projectile is launched at an angle 60° to the horizontal  with some initial speed 45 m/s.

The cliff is 265 m high.

(A) The final velocity of the projectile is given by :

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H=\dfrac{v_i^2\sin^2\theta}{2g}\\\\H=\dfrac{45^2\times \sin^2(60)}{2\times 9.8}\\\\H=77.48\ m

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Answer:

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