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bija089 [108]
3 years ago
15

Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1. 2 m high. Student 2 pushes an identical box up a 5 m ra

mp from the floor to the top of the same table. Which student did the MOST work?.
Physics
1 answer:
valina [46]3 years ago
5 0

The student 2 did the MOST work because he pushed the box to a greater height.

The given parameters:

  • <em>Force applied by Student 1 = 500 N</em>
  • <em>Height of table for student 1 = 1.2 m</em>
  • <em>Height of ramp for student 2 = 5 m</em>

The work done by student 1 is calculated as follows;

Work = P.E = mgh

P.E = 1.2mg

The work done by the student 2 is calculated as;

P.E = 5mg

where;

  • <em>m </em><em>is the </em><em>mass </em><em>of the box</em>

Thus, we can conclude that the student 2 did the MOST work.

Learn more about work done here: brainly.com/question/8119756

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The magnetic moment is -

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We have current carrying single circular loop placed in a magnetic field

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We have to determine the Magnetic moment of the loop.

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The formula to calculate the magnetic moment of the loop is -

M = NIA

where -

N -  Number of turns

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According to the question, we have -

I = 17mA = 0.017A

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Now -

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Using the formula -

M = NIA

M = \piNIr^{2}

M = 3.14 x 1 x 0.017 x 0.32 x 0.32

M = 3.14 x 4 x 0.017

M = 5.5 x 10^{-3} Am^{2}

Hence, the magnetic moment is -

M = 5.5 x 10^{-3} Am^{2}

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brainly.com/question/13933686

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A 4.0-kilogram ball moving at 8.0 m/s to the right collides with a 1.0-kilogram ball at rest. After the collision, the 4.0-kilog
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