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bija089 [108]
3 years ago
15

Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1. 2 m high. Student 2 pushes an identical box up a 5 m ra

mp from the floor to the top of the same table. Which student did the MOST work?.
Physics
1 answer:
valina [46]3 years ago
5 0

The student 2 did the MOST work because he pushed the box to a greater height.

The given parameters:

  • <em>Force applied by Student 1 = 500 N</em>
  • <em>Height of table for student 1 = 1.2 m</em>
  • <em>Height of ramp for student 2 = 5 m</em>

The work done by student 1 is calculated as follows;

Work = P.E = mgh

P.E = 1.2mg

The work done by the student 2 is calculated as;

P.E = 5mg

where;

  • <em>m </em><em>is the </em><em>mass </em><em>of the box</em>

Thus, we can conclude that the student 2 did the MOST work.

Learn more about work done here: brainly.com/question/8119756

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Answer:

The charge flows in coulombs is

dq=1.843x10^{-5}C

Explanation:

The current magnitude of current is given by the resistance and the induced Emf as:

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\frac{dq}{dt}=\frac{dF}{Rdt}=dq=N*\frac{dF}{R}

dq=\frac{N*\beta*A*(Cos(\alpha_f)-Cos(\alpha_i}{R}

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Replacing :

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3 years ago
Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?
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Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

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If a neutral atom <u>loses electrons</u>, it remains with an excess of positive charge and transforms into a positive ion or <u>cation</u>, whereas if a neutral atom <u>gains electrons</u>, it acquires an excess of negative charge and transforms into a negative ion or <u>anion</u>.

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