Answer:
5.68*10^-5 °C
Explanation:
ADC is an acronym that means analog to digital conversion.
The numbers of bit in any ADC is the level of Voltage it possess.
The question states 32 bits, this means that it's total voltage levels is 2^32
Also, the question gives us a range of 10 V for the ADC. Now we can evaluate the resolution of the voltage as:
Δv = 10 / (2^32)
Δv = 10 / 4.29^9
Δv = 2.33*10^-9
The thermocouple sensitivity is 41 micro volts/°C
Thermocouple sensitivity = Δv/ΔT, where ΔT is the temperature change
ΔT = Δv/thermocouple sensitivity
ΔT = 2.33*10^-9 / 41*10^-6
ΔT = 5.68*10^-5 °C
Thus, the smallest temperature change is 5.68*10^-5 °C
Answer:
The motion of a simple pendulum is very close to Simple Harmonic Motion (SHM). SHM results whenever a restoring force is proportional to the displacement, a relationship often known as Hooke's Law when applied to springs. Where F is the restoring force, k is the spring constant, and x is the displacement.
where θ is the angle the pendulum makes with the vertical. For small angles, sin(θ)∼θ, which would then lead to simple harmonic motion. For large angles, this approximation no longer holds, and the motion is not considered to be simple harmonic motion.
Answer:
The answer to your question is 5.5 x 10¹² kg/km³
Explanation:
Data
density = rho = X
mass = 5.94 x 10²⁴ kg
volume = 1.08 x 10¹² km³
Process
To solve this problem use the density formula and simplify it to find the result.
Formula
density =
Substitution
density =
Simplification and result
density = 5.5 x 10¹² kg/km³
If an object has a density greater than the liquid in which it is placed it will sink.
Explanation:
Density of the object can be known by its mass and volume.
If two objects have same volume but different masses it means the one having more mass will have higher density. Density is amount of mass per unit volume.
Objects that are tightly packed have higher density.
According to Archimedes' principle when a body is fully immersed that an upward buoyant force is equal to weight of the fluid that object displaces.
Springs in series will experience the same force all throughout and the elongation will add up. Springs in parallel will experience different forces and the elongation will be the same for each. The ranking will be from lowest to highest:
Case 3
Case 2
Case 1
Case 4
Case 5