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cupoosta [38]
3 years ago
11

If the angle of incidence of a light source to a shiny surface is 30 degrees, what will the angle

Physics
2 answers:
Vinvika [58]3 years ago
8 0
Answer : 30 degrees
*** HOPE THIS HELP YOU***
Virty [35]3 years ago
5 0
<h3>Answer: D) 30</h3>

Angle of incidence always equals angle of reflection. Think of a tennis ball being hit into a wall. The ball will bounce off at the same angle that it approached with. The angles mentioned are formed through the line called the "normal", which is the line perpendicular to the surface.

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An AC generator supplies 44 rms volts to a 60-Ω resistor at 60 Hz. What is the maximum current in the resistor?
Brilliant_brown [7]

Answer:

1.0639 A

Explanation:

We have given rms voltage V = 44 volt

Resistance = 60 ohm

According to ohm's law V=iR

So 44=i\times 60

i=\frac{44}{60}=0.7333A this is the rms current but we have to find the maximum current

So maximum current i_m=\sqrt{2}i_{rms}=1.414\times 0.7333=1.03693A

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The answer is C

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Does the thickness of the wire affect the strength of an electroscope
TiliK225 [7]
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According to the cell theory where do cells come from?
Soloha48 [4]

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Read 2 more answers
What is the electric potential energy of an electron at the negative end of the cable, relative to the positive end of the cable
VashaNatasha [74]

Answer:

Electric potential energy at the negative terminal: 1.92\cdot 10^{-18}J

Explanation:

When a particle with charge q travels across a potential difference \Delta V, then its change in electric potential energy is

\Delta U = q \Delta V

In this problem, we know that:

The particle is an electron, so its charge is

q=-1.60\cdot 10^{-19}C

We also know that the positive terminal is at potential

V_+=0V

While the negative terminal is at potential

V_-=-12 V

Therefore, the potential difference (final minus initial) is

\Delta V = -12-0 = -12 V

So, the change in potential energy of the electron is

\Delta U = (-1.6\cdot 10^{-19})(-12)=1.92\cdot 10^{-18}J

This means that the electron when it is at the negative terminal has 1.92\cdot 10^{-18}J of energy more than when it is at the positive terminal.

Since the potential at the positive terminal is 0, this means that the electric potential energy of the electron at the negative end is

1.92\cdot 10^{-18}J

3 0
4 years ago
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