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Makovka662 [10]
2 years ago
7

At the end of chemical reactions, what is the total mass of the reactants compared to the total mass of the products?

Chemistry
1 answer:
zhuklara [117]2 years ago
5 0
Mass is never lost or gained in chemical reactions. We say that mass is always conserved. In other words, the total mass of products at the end of the reaction is equal to the total mass of the reactants at the beginning. This is because no atoms are created or destroyed during chemical reactions.
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Kate wrote the steps of the carbon cycle to describe how carbon is cycled through specific organisms. The steps are in random or
Kobotan [32]
<h3>Answer:</h3>

3, 2, 1, 4

<h3>Further explanation:</h3>

The process of photosynthesis is the process of converting carbon dioxide and water into energy in the form of carbohydrates using sunlight. Usually done by plants that have leafy za called chlorophyll.

Carbohydrates themselves are formed from the C-carbon, H-hydrogen and O-oxygen components

Rabbit food is carrots that contain carbohydrates, which are part of the photosynthesis process

3. The carrot plant takes in carbon dioxide from the air during photosynthesis.

Reaction

6CO₂ + 6H₂O ⇒ C₆H₁₂O₆ + 6O₂

2. The rabbit eats the carrot plant.

Rabbits meet their carbohydrate source for energy by eating carrots

1. The rabbit decomposes.

Rabbits in time will experience a process of decomposition

4 - Carbon compounds are returned to the soil.

The carbon content in rabbits will also be decomposed into the soil again

3 0
3 years ago
Read 2 more answers
Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) H 2O (l) Ca(OH) 2 (s) In a parti
Nimfa-mama [501]
Find the moles of CaO

divide mass (2.0g) by the RFM which is 56 (Ca is 40 add that to O which is 16 making 56) this gives 0.0356 moles.

Find the theoretical mass by multiplying the moles of CaO (which is 0.0356 as there are no balancing number making the ratio 1:1) by the RFM of Ca(OH)2 which is 74 (40+16+16+1+1)

74 (Ca(OH)2 RFM) x 0.0357 (CaO moles) = 2.6g which is the theoretical mass of Ca(OH)2

Find percentage yield by dividing the actual mass of Ca(OH)2 by the theoretical and then x100 this Should give you 82.3%
8 0
3 years ago
A sample of helium gas has a volume of 2.0 L at a pressure of 4.0 atm. What is the volume of gas at 380 mmHg
Lilit [14]
From equation;
P1V1=P2V2
V2=P1V1÷P2
since P2=380mmHg
now;1atm=760mmHg
how about 380mmHg is equal to how many atm?
380×1÷760=0.5atm
P2 now is equal to 0.5atm
back from equation;
P1V1=P2V2
V2=P1V1÷P2
V2=4.0atm×2.0L÷0.5atm
V2=16L
therefore V2=16L.
5 0
2 years ago
Why is it Xe????????????????
Tamiku [17]

Answer:

Here's what I get.

Explanation:

Ba is element 56. Its electron configuration is

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

That's a lot of writing.

To lessen the work, chemists have developed the noble gas notation.

The core electrons of Ba (listed in boldface) have the same electron configuration as Xe, the noble gas found two atoms earlier in the Periodic Table.

Chemists replace the core electron configuration with the symbol of the corresponding noble gas.

The noble gas notation for Ba becomes

Ba: [Xe]6s².

5 0
3 years ago
How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!
RoseWind [281]
<h3>Answer:</h3>

251 mol Xe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.51 × 10²⁶ atoms Xe

[Solve] moles Xe

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 250.747 \ mol \ Xe

<u>Step 4: Check</u>

<em>Follow sig fig rule and round. We are given 3 sig figs.</em>

250.747 mol Xe ≈ 251 mol Xe

3 0
2 years ago
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